我想用Python编写一个函数,根据输入索引的值返回不同的固定值。
在其他语言中,我会使用switch或case语句,但Python似乎没有switch语句。在此场景中,推荐的Python解决方案是什么?
我想用Python编写一个函数,根据输入索引的值返回不同的固定值。
在其他语言中,我会使用switch或case语句,但Python似乎没有switch语句。在此场景中,推荐的Python解决方案是什么?
当前回答
在阅读了公认的答案后,我感到非常困惑,但这一切都清楚了:
def numbers_to_strings(argument):
switcher = {
0: "zero",
1: "one",
2: "two",
}
return switcher.get(argument, "nothing")
该代码类似于:
function(argument){
switch(argument) {
case 0:
return "zero";
case 1:
return "one";
case 2:
return "two";
default:
return "nothing";
}
}
有关字典映射到函数的详细信息,请查看源代码。
其他回答
我做了一个switch-case实现,它在外部不太使用if(它仍然在类中使用if)。
class SwitchCase(object):
def __init__(self):
self._cases = dict()
def add_case(self,value, fn):
self._cases[value] = fn
def add_default_case(self,fn):
self._cases['default'] = fn
def switch_case(self,value):
if value in self._cases.keys():
return self._cases[value](value)
else:
return self._cases['default'](0)
这样使用:
from switch_case import SwitchCase
switcher = SwitchCase()
switcher.add_case(1, lambda x:x+1)
switcher.add_case(2, lambda x:x+3)
switcher.add_default_case(lambda _:[1,2,3,4,5])
print switcher.switch_case(1) #2
print switcher.switch_case(2) #5
print switcher.switch_case(123) #[1, 2, 3, 4, 5]
我一直喜欢这样做
result = {
'a': lambda x: x * 5,
'b': lambda x: x + 7,
'c': lambda x: x - 2
}[value](x)
从这里开始
我在谷歌搜索上找不到简单的答案。但我还是想通了。这真的很简单。决定把它贴出来,也许可以防止别人的头上少刮几下。关键是简单的“in”和元组。下面是带有直通的switch语句行为,包括RANDOM直通。
l = ['Dog', 'Cat', 'Bird', 'Bigfoot',
'Dragonfly', 'Snake', 'Bat', 'Loch Ness Monster']
for x in l:
if x in ('Dog', 'Cat'):
x += " has four legs"
elif x in ('Bat', 'Bird', 'Dragonfly'):
x += " has wings."
elif x in ('Snake',):
x += " has a forked tongue."
else:
x += " is a big mystery by default."
print(x)
print()
for x in range(10):
if x in (0, 1):
x = "Values 0 and 1 caught here."
elif x in (2,):
x = "Value 2 caught here."
elif x in (3, 7, 8):
x = "Values 3, 7, 8 caught here."
elif x in (4, 6):
x = "Values 4 and 6 caught here"
else:
x = "Values 5 and 9 caught in default."
print(x)
提供:
Dog has four legs
Cat has four legs
Bird has wings.
Bigfoot is a big mystery by default.
Dragonfly has wings.
Snake has a forked tongue.
Bat has wings.
Loch Ness Monster is a big mystery by default.
Values 0 and 1 caught here.
Values 0 and 1 caught here.
Value 2 caught here.
Values 3, 7, 8 caught here.
Values 4 and 6 caught here
Values 5 and 9 caught in default.
Values 4 and 6 caught here
Values 3, 7, 8 caught here.
Values 3, 7, 8 caught here.
Values 5 and 9 caught in default.
如果您想要默认值,可以使用dictionary get(key[,default])函数:
def f(x):
return {
'a': 1,
'b': 2
}.get(x, 9) # 9 will be returned default if x is not found
我要把我的两分钱放在这里。Python中没有case/switch语句的原因是因为Python遵循“只有一种正确的方法”的原则。很明显,您可以想出各种方法来重新创建switch/case功能,但实现这一点的Python方法是if/elf构造。即。,
if something:
return "first thing"
elif somethingelse:
return "second thing"
elif yetanotherthing:
return "third thing"
else:
return "default thing"
我只是觉得PEP 8应该在这里获得认可。Python的一个优点是它的简单和优雅。这在很大程度上源于PEP8中提出的原则,包括“只有一种正确的方法可以做某事。”