如何从内置web浏览器而不是应用程序中的代码打开URL?

我试过了:

try {
    Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(download_link));
    startActivity(myIntent);
} catch (ActivityNotFoundException e) {
    Toast.makeText(this, "No application can handle this request."
        + " Please install a webbrowser",  Toast.LENGTH_LONG).show();
    e.printStackTrace();
}

但我有个例外:

No activity found to handle Intent{action=android.intent.action.VIEW data =www.google.com

当前回答

只需使用简短的一个,即可在浏览器中打开您的Url:

Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("YourUrlHere"));
startActivity(browserIntent);

其他回答

如果您想向用户显示一个带有所有浏览器列表的对话框,以便他可以选择首选项,下面是示例代码:

private static final String HTTPS = "https://";
private static final String HTTP = "http://";

public static void openBrowser(final Context context, String url) {

     if (!url.startsWith(HTTP) && !url.startsWith(HTTPS)) {
            url = HTTP + url;
     }

     Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
     context.startActivity(Intent.createChooser(intent, "Choose browser"));// Choose browser is arbitrary :)

}

检查您的url是否正确。对我来说,url前面有一个不需要的空格。

来自Anko库方法

fun Context.browse(url: String, newTask: Boolean = false): Boolean {
    try {
        val intent = Intent(Intent.ACTION_VIEW)
        intent.data = Uri.parse(url)
        if (newTask) {
            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
        }
        startActivity(intent)
        return true
    } catch (e: ActivityNotFoundException) {
        e.printStackTrace()
        return false
    }
}

在Android 11中打开URL链接的新的更好方法。

  try {
        val intent = Intent(ACTION_VIEW, Uri.parse(url)).apply {
            // The URL should either launch directly in a non-browser app
            // (if it’s the default), or in the disambiguation dialog
            addCategory(CATEGORY_BROWSABLE)
            flags = FLAG_ACTIVITY_NEW_TASK or FLAG_ACTIVITY_REQUIRE_NON_BROWSER or
                    FLAG_ACTIVITY_REQUIRE_DEFAULT
        }
        startActivity(intent)
    } catch (e: ActivityNotFoundException) {
        // Only browser apps are available, or a browser is the default app for this intent
        // This code executes in one of the following cases:
        // 1. Only browser apps can handle the intent.
        // 2. The user has set a browser app as the default app.
        // 3. The user hasn't set any app as the default for handling this URL.
        openInCustomTabs(url)
    }

参考文献:

https://medium.com/androiddevelopers/package-visibility-in-android-11-cc857f221cd9和https://developer.android.com/training/package-visibility/use-cases#avoid-a-消除歧义对话框

android.webkit.URLUtil自Api级别1(android 1.0)以来,guessUrl(String)方法工作得非常好(即使使用file://或data://)。用作:

String url = URLUtil.guessUrl(link);

// url.com            ->  http://url.com/     (adds http://)
// http://url         ->  http://url.com/     (adds .com)
// https://url        ->  https://url.com/    (adds .com)
// url                ->  http://www.url.com/ (adds http://www. and .com)
// http://www.url.com ->  http://www.url.com/ 
// https://url.com    ->  https://url.com/
// file://dir/to/file ->  file://dir/to/file
// data://dataline    ->  data://dataline
// content://test     ->  content://test

在“活动”调用中:

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(URLUtil.guessUrl(download_link)));

if (intent.resolveActivity(getPackageManager()) != null)
    startActivity(intent);

有关详细信息,请查看完整的guessUrl代码。