在Objective-C中有没有(stringByAppendingString:)字符串连接的快捷方式，或者一般使用NSString的快捷方式?
例如，我想做:
NSString *myString = @"This";
NSString *test = [myString stringByAppendingString:@" is just a test"];
更像是:
string myString = "This";
string test = myString + " is just a test";
当前回答
listOfCatalogIDs =[@[@"id[]=",listOfCatalogIDs] componentsJoinedByString:@""];
其他回答
NSString *label1 = @"Process Name: ";
NSString *label2 = @"Process Id: ";
NSString *processName = [[NSProcessInfo processInfo] processName];
NSString *processID = [NSString stringWithFormat:@"%d", [[NSProcessInfo processInfo] processIdentifier]];
NSString *testConcat = [NSString stringWithFormat:@"%@ %@ %@ %@", label1, processName, label2, processID];
如果你有两个NSString字面量，你也可以这样做:
NSString *joinedFromLiterals = @"ONE " @"MILLION " @"YEARS " @"DUNGEON!!!";
这对于加入#定义也很有用:
#define STRINGA @"Also, I don't know "
#define STRINGB @"where food comes from."
#define JOINED STRINGA STRINGB
享受。
这里有一个简单的方法，使用新的数组文字语法:
NSString * s = [@[@"one ", @"two ", @"three"] componentsJoinedByString:@""];
^^^^^^^ create array ^^^^^
^^^^^^^ concatenate ^^^^^
正在尝试在lldb窗格中执行以下操作
[NSString stringWithFormat:@"%@/%@/%@", three, two, one];
这错误。
而是使用alloc和initWithFormat方法:
[[NSString alloc] initWithFormat:@"%@/%@/%@", @"three", @"two", @"one"];
你可以使用NSArray as
NSString *string1=@"This"
NSString *string2=@"is just"
NSString *string3=@"a test"
NSArray *myStrings = [[NSArray alloc] initWithObjects:string1, string2, string3,nil];
NSString *fullLengthString = [myStrings componentsJoinedByString:@" "];
or
你可以使用
NSString *imageFullName=[NSString stringWithFormat:@"%@ %@ %@.", string1,string2,string3];
