在Objective-C中有没有(stringByAppendingString:)字符串连接的快捷方式,或者一般使用NSString的快捷方式?

例如,我想做:

NSString *myString = @"This";
NSString *test = [myString stringByAppendingString:@" is just a test"];

更像是:

string myString = "This";
string test = myString + " is just a test";

当前回答

这样使用stringByAppendingString:

NSString *string1, *string2, *result;

string1 = @"This is ";
string2 = @"my string.";

result = [result stringByAppendingString:string1];
result = [result stringByAppendingString:string2];

OR

result = [result stringByAppendingString:@"This is "];
result = [result stringByAppendingString:@"my string."];

其他回答

NSNumber *lat = [NSNumber numberWithDouble:destinationMapView.camera.target.latitude];
NSNumber *lon = [NSNumber numberWithDouble:destinationMapView.camera.target.longitude];
NSString *DesconCatenated = [NSString stringWithFormat:@"%@|%@",lat,lon];

使c = [a stringByAppendingString: b]更短的唯一方法是在st点附近使用自动补全。+运算符是C的一部分,它不知道Objective-C对象。

我一直在看这篇文章,最后总是整理答案,找到一个简单的解决方案,可以根据需要处理尽可能多的变量:

[NSString stringWithFormat:@"%@/%@/%@", three, two, one];

例如:

NSString *urlForHttpGet = [NSString stringWithFormat:@"http://example.com/login/username/%@/userid/%i", userName, userId];

这样使用stringByAppendingString:

NSString *string1, *string2, *result;

string1 = @"This is ";
string2 = @"my string.";

result = [result stringByAppendingString:string1];
result = [result stringByAppendingString:string2];

OR

result = [result stringByAppendingString:@"This is "];
result = [result stringByAppendingString:@"my string."];

创建一个方法:

- (NSString *)strCat: (NSString *)one: (NSString *)two
{
    NSString *myString;
    myString = [NSString stringWithFormat:@"%@%@", one , two];
    return myString;
}

然后,在任何你需要它的函数中,将你的字符串或文本字段设置为这个函数的返回值。

或者,要做一个快捷方式,将NSString转换成c++字符串,并在那里使用'+'。