其他答案有一个问题:它们依赖于你所做的操作，而不是链接本身来决定是在Safari中加载还是在webview中加载。

有时候这正是你想要的，这很好;但有些时候，特别是当你的页面中有锚点链接时，你想在Safari中只打开外部链接，而不是内部链接。在这种情况下，您应该检查URL。请求的主机属性。

我使用这段代码来检查正在解析的URL中是否有主机名，或者它是否是嵌入的html:

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
    static NSString *regexp = @"^(([a-zA-Z]|[a-zA-Z][a-zA-Z0-9-]*[a-zA-Z0-9])[.])+([A-Za-z]|[A-Za-z][A-Za-z0-9-]*[A-Za-z0-9])$";
    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", regexp];

    if ([predicate evaluateWithObject:request.URL.host]) {
        [[UIApplication sharedApplication] openURL:request.URL];
        return NO; 
    } else {
        return YES; 
    }
}

当然，您可以调整正则表达式以满足您的需要。

将这个添加到UIWebView委托:

(经过编辑以检查导航类型。你也可以通过file:// requests传递相对链接)

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
    if (navigationType == UIWebViewNavigationTypeLinkClicked ) {
        [[UIApplication sharedApplication] openURL:[request URL]];
        return NO;
    }

    return YES;
}

斯威夫特版本:

func webView(webView: UIWebView, shouldStartLoadWithRequest request: NSURLRequest, navigationType: UIWebViewNavigationType) -> Bool {
        if navigationType == UIWebViewNavigationType.LinkClicked {
            UIApplication.sharedApplication().openURL(request.URL!)
            return false
        }
        return true
    }

Swift 3版本:

func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
    if navigationType == UIWebViewNavigationType.linkClicked {
        UIApplication.shared.openURL(request.url!)
        return false
    }
    return true
}

Swift 4版本:

func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebView.NavigationType) -> Bool {
    guard let url = request.url, navigationType == .linkClicked else { return true }
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
    return false
}

更新

由于openURL在iOS 10中已弃用:

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
        if (navigationType == UIWebViewNavigationTypeLinkClicked ) {
            UIApplication *application = [UIApplication sharedApplication];
            [application openURL:[request URL] options:@{} completionHandler:nil];
            return NO;
        }

        return YES;
}

公认的答案行不通。

如果你的页面通过Javascript加载url, navigationType将是UIWebViewNavigationTypeOther。不幸的是，这也包括后台页面加载，如分析。

要检测页面导航，需要比较[request URL]和[request mainDocumentURL]。

这个解决方案将在所有情况下工作:

- (BOOL)webView:(UIWebView *)view shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)type
{
    if ([[request URL] isEqual:[request mainDocumentURL]])
    {
        [[UIApplication sharedApplication] openURL:[request URL]];
        return NO;
    }
    else
    {       
        return YES;
    }
}

对user306253的回答的一个快速评论:小心，当你自己尝试在UIWebView中加载一些东西时(即即使从代码中加载)，这个方法将防止它发生。

你能做什么来防止这种情况(感谢韦德):

if (inType == UIWebViewNavigationTypeLinkClicked) {
    [[UIApplication sharedApplication] openURL:[inRequest URL]];
    return NO;
}

return YES;

你可能还想处理UIWebViewNavigationTypeFormSubmitted和UIWebViewNavigationTypeFormResubmitted类型。

不建议使用UIWebView和UIWebViewDelegate。你将不被允许将更新推送到Appstore。参考

使用WKWebView和WKNavigationDelegate

示例代码:

class YourClass: WKNavigationDelegate {

    override public func viewDidLoad() {
        super.viewDidLoad()
        let webView = WKWebView()
        webView.navigationDelegate = self
        self.view.addaddSubview(webView)
    }
    
    public func webView(_ webView: WKWebView,
                    didReceive challenge: URLAuthenticationChallenge,
                    completionHandler: @escaping (URLSession.AuthChallengeDisposition, URLCredential?) -> Void) {
        let cred = URLCredential(trust: challenge.protectionSpace.serverTrust!)
        completionHandler(.useCredential, cred)
    }

    public func webView(_ webView: WKWebView,
                    decidePolicyFor navigationAction: WKNavigationAction,
                    decisionHandler: @escaping (WKNavigationActionPolicy) -> Swift.Void) {
    
        self.webView.load(navigationAction.request)
        decisionHandler(.allow)
    }
}

下面是Xamarin iOS版的drawnonward的答案。

class WebviewDelegate : UIWebViewDelegate {
    public override bool ShouldStartLoad (UIWebView webView, NSUrlRequest request, UIWebViewNavigationType navigationType) {
        if (navigationType == UIWebViewNavigationType.LinkClicked) {
            UIApplication.SharedApplication.OpenUrl (request.Url);
            return false;
        }
        return true;
    }
}