using System;
using System.IO;

// Get the current directory and make it a DirectoryInfo object.
// Do not use Environment.CurrentDirectory, vistual studio 
// and visual studio code will return different result:
// Visual studio will return @"projectDir\bin\Release\netcoreapp2.0\", yet 
// vs code will return @"projectDir\"
var currentDirectory = new DirectoryInfo(AppDomain.CurrentDomain.BaseDirectory);

// On windows, the current directory is the compiled binary sits,
// so string like @"bin\Release\netcoreapp2.0\" will follow the project directory. 
// Hense, the project directory is the great grand-father of the current directory.
string projectDirectory = currentDirectory.Parent.Parent.Parent.FullName;

这个解决方案很适合我，在开发和测试和PROD服务器上使用ASP。NET MVC5通过c#:

var projectDir = Path.GetDirectoryName(AppDomain.CurrentDomain.BaseDirectory);

如果你需要项目目录中的项目配置文件使用:

$(ProjectDir)

.Parent.Parent.Parent.Parent.FullName Directory.GetParent (Directory.GetCurrentDirectory ())

会给你项目目录。

Try:

var pathRegex = new Regex(@"\\bin(\\x86|\\x64)?\\(Debug|Release)$", RegexOptions.Compiled);
var directory = pathRegex.Replace(Directory.GetCurrentDirectory(), String.Empty);

这是不同于其他的解决方案，也考虑到可能的x86或x64构建。

您可以尝试这两种方法中的一种。

string startupPath = System.IO.Directory.GetCurrentDirectory();

string startupPath = Environment.CurrentDirectory;

告诉我，你觉得哪个更好

using System;
using System.IO;

// Get the current directory and make it a DirectoryInfo object.
// Do not use Environment.CurrentDirectory, vistual studio 
// and visual studio code will return different result:
// Visual studio will return @"projectDir\bin\Release\netcoreapp2.0\", yet 
// vs code will return @"projectDir\"
var currentDirectory = new DirectoryInfo(AppDomain.CurrentDomain.BaseDirectory);

// On windows, the current directory is the compiled binary sits,
// so string like @"bin\Release\netcoreapp2.0\" will follow the project directory. 
// Hense, the project directory is the great grand-father of the current directory.
string projectDirectory = currentDirectory.Parent.Parent.Parent.FullName;