你觉得这个怎么样?非常简洁:)

SELECT OBJECT_NAME(parent_id) Table_or_ViewNM,
      name TriggerNM,
      is_instead_of_trigger,
      is_disabled
FROM sys.triggers
WHERE parent_class_desc = 'OBJECT_OR_COLUMN'
ORDER BY OBJECT_NAME(parent_id),
Name ;

这可能会有所帮助。

SELECT DISTINCT o.[name] AS [Table]
FROM    [sysobjects] o
JOIN    [sysobjects] tr
    ON  o.[id] = tr.[parent_obj]
WHERE   tr.[type] = 'tr'
ORDER BY [Table]

Get a list of tables and all their triggers.

SELECT DISTINCT o.[name] AS [Table], tr.[name] AS [Trigger]
FROM    [sysobjects] o
JOIN    [sysobjects] tr
    ON  o.[id] = tr.[parent_obj]
WHERE   tr.[type] = 'tr'
ORDER BY [Table], [Trigger]

SELECT 
     sysobjects.name AS trigger_name   ,OBJECT_NAME(parent_obj) AS table_name ,s.name AS table_schema 
    ,USER_NAME(sysobjects.uid) AS trigger_owner 


    ,OBJECTPROPERTY( id, 'ExecIsUpdateTrigger') AS isupdate 
    ,OBJECTPROPERTY( id, 'ExecIsDeleteTrigger') AS isdelete 
    ,OBJECTPROPERTY( id, 'ExecIsInsertTrigger') AS isinsert 
    ,OBJECTPROPERTY( id, 'ExecIsAfterTrigger') AS isafter 
    ,OBJECTPROPERTY( id, 'ExecIsInsteadOfTrigger') AS isinsteadof 
    ,OBJECTPROPERTY(id, 'ExecIsTriggerDisabled') AS [disabled] 
FROM sysobjects 

INNER JOIN sysusers 
    ON sysobjects.uid = sysusers.uid 

INNER JOIN sys.tables t 
    ON sysobjects.parent_obj = t.object_id 

INNER JOIN sys.schemas s 
    ON t.schema_id = s.schema_id 

WHERE sysobjects.type = 'TR' 

这对我很有用

我最近有同样的任务，我使用以下sql server 2012 db。使用management studio并连接到要搜索的数据库。然后执行以下脚本。

Select 
[tgr].[name] as [trigger name], 
[tbl].[name] as [table name]

from sysobjects tgr 

join sysobjects tbl
on tgr.parent_obj = tbl.id

WHERE tgr.xtype = 'TR'

一个困难是文本或描述有换行。我的笨拙的拼凑，使它在更表格的东西，是添加一个HTML文字到SELECT子句，复制并粘贴到记事本，保存与HTML扩展，在浏览器中打开，然后复制并粘贴到一个电子表格。 例子

SELECT obj.NAME AS TBL,trg.name,sm.definition,'<br>'
FROM SYS.OBJECTS obj
LEFT JOIN (SELECT trg1.object_id,trg1.parent_object_id,trg1.name FROM sys.objects trg1 WHERE trg1.type='tr' AND trg1.name like 'update%') trg
 ON obj.object_id=trg.parent_object_id
LEFT JOIN (SELECT sm1.object_id,sm1.definition FROM sys.sql_modules sm1 where sm1.definition like '%suser_sname()%') sm ON trg.object_id=sm.object_id
WHERE obj.type='u'
ORDER BY obj.name;

你可能仍然需要使用标签将描述放到一个字段中，但至少它会在一行上，我发现这非常有帮助。

上面的代码是错误的，如下所示:

SELECT 
    sysobjects.name AS trigger_name 
    --,USER_NAME(sysobjects.uid) AS trigger_owner 
    --,s.name AS table_schema 
    --,OBJECT_NAME(parent_obj) AS table_name 
    --,OBJECTPROPERTY( id, 'ExecIsUpdateTrigger') AS isupdate 
    --,OBJECTPROPERTY( id, 'ExecIsDeleteTrigger') AS isdelete 
    --,OBJECTPROPERTY( id, 'ExecIsInsertTrigger') AS isinsert 
    --,OBJECTPROPERTY( id, 'ExecIsAfterTrigger') AS isafter 
    --,OBJECTPROPERTY( id, 'ExecIsInsteadOfTrigger') AS isinsteadof 
    --,OBJECTPROPERTY(id, 'ExecIsTriggerDisabled') AS [disabled] 
FROM sysobjects 
/*
INNER JOIN sysusers 
    ON sysobjects.uid = sysusers.uid 
*/  
INNER JOIN sys.tables t 
    ON sysobjects.parent_obj = t.object_id 

INNER JOIN sys.schemas s 
    ON t.schema_id = s.schema_id 
WHERE sysobjects.type = 'TR' 
EXCEPT
SELECT OBJECT_NAME(parent_id) as Table_Name FROM sys.triggers