假设我有一个字符串:
string str = "1111222233334444";
我如何把这个字符串分成一定大小的块?
例如,将它分解为4的大小将返回字符串:
"1111"
"2222"
"3333"
"4444"
假设我有一个字符串:
string str = "1111222233334444";
我如何把这个字符串分成一定大小的块?
例如,将它分解为4的大小将返回字符串:
"1111"
"2222"
"3333"
"4444"
当前回答
使用IX库中的Buffer扩展
static IEnumerable<string> Split( this string str, int chunkSize )
{
return str.Buffer(chunkSize).Select(l => String.Concat(l));
}
其他回答
static IEnumerable<string> Split(string str, int chunkSize)
{
return Enumerable.Range(0, str.Length / chunkSize)
.Select(i => str.Substring(i * chunkSize, chunkSize));
}
请注意,可能需要额外的代码来优雅地处理边缘情况(null或空输入字符串,chunkSize == 0,输入字符串长度不能被chunkSize整除,等等)。最初的问题没有为这些边缘情况指定任何需求,在现实生活中,需求可能会有所不同,因此它们超出了这个答案的范围。
六年后o_O
仅仅因为
public static IEnumerable<string> Split(this string str, int chunkSize, bool remainingInFront)
{
var count = (int) Math.Ceiling(str.Length/(double) chunkSize);
Func<int, int> start = index => remainingInFront ? str.Length - (count - index)*chunkSize : index*chunkSize;
Func<int, int> end = index => Math.Min(str.Length - Math.Max(start(index), 0), Math.Min(start(index) + chunkSize - Math.Max(start(index), 0), chunkSize));
return Enumerable.Range(0, count).Select(i => str.Substring(Math.Max(start(i), 0),end(i)));
}
or
private static Func<bool, int, int, int, int, int> start = (remainingInFront, length, count, index, size) =>
remainingInFront ? length - (count - index) * size : index * size;
private static Func<bool, int, int, int, int, int, int> end = (remainingInFront, length, count, index, size, start) =>
Math.Min(length - Math.Max(start, 0), Math.Min(start + size - Math.Max(start, 0), size));
public static IEnumerable<string> Split(this string str, int chunkSize, bool remainingInFront)
{
var count = (int)Math.Ceiling(str.Length / (double)chunkSize);
return Enumerable.Range(0, count).Select(i => str.Substring(
Math.Max(start(remainingInFront, str.Length, count, i, chunkSize), 0),
end(remainingInFront, str.Length, count, i, chunkSize, start(remainingInFront, str.Length, count, i, chunkSize))
));
}
AFAIK所有的边缘情况都处理好了。
Console.WriteLine(string.Join(" ", "abc".Split(2, false))); // ab c
Console.WriteLine(string.Join(" ", "abc".Split(2, true))); // a bc
Console.WriteLine(string.Join(" ", "a".Split(2, true))); // a
Console.WriteLine(string.Join(" ", "a".Split(2, false))); // a
public static List<string> SplitByMaxLength(this string str)
{
List<string> splitString = new List<string>();
for (int index = 0; index < str.Length; index += MaxLength)
{
splitString.Add(str.Substring(index, Math.Min(MaxLength, str.Length - index)));
}
return splitString;
}
从。net 6开始,我们还可以使用Chunk方法:
var result = str
.Chunk(4)
.Select(x => new string(x))
.ToList();
这应该比使用LINQ或这里使用的其他方法更快更有效。
public static IEnumerable<string> Splice(this string s, int spliceLength)
{
if (s == null)
throw new ArgumentNullException("s");
if (spliceLength < 1)
throw new ArgumentOutOfRangeException("spliceLength");
if (s.Length == 0)
yield break;
var start = 0;
for (var end = spliceLength; end < s.Length; end += spliceLength)
{
yield return s.Substring(start, spliceLength);
start = end;
}
yield return s.Substring(start);
}