假设我有一个字符串:
string str = "1111222233334444";
我如何把这个字符串分成一定大小的块?
例如,将它分解为4的大小将返回字符串:
"1111"
"2222"
"3333"
"4444"
假设我有一个字符串:
string str = "1111222233334444";
我如何把这个字符串分成一定大小的块?
例如,将它分解为4的大小将返回字符串:
"1111"
"2222"
"3333"
"4444"
当前回答
for (int i = 0; i <= Convert.ToInt32(Math.Truncate(Convert.ToDecimal(_string.Length / _chunkSize))); i++)
{
var _currentChunk = _string.Substring(i * _chunkSize, Math.Min(_chunkSize, _string.Length - i * _chunkSize));
//do something with current chunk
}
其他回答
我认为这是一个直截了当的答案:
public static IEnumerable<string> Split(this string str, int chunkSize)
{
if(string.IsNullOrEmpty(str) || chunkSize<1)
throw new ArgumentException("String can not be null or empty and chunk size should be greater than zero.");
var chunkCount = str.Length / chunkSize + (str.Length % chunkSize != 0 ? 1 : 0);
for (var i = 0; i < chunkCount; i++)
{
var startIndex = i * chunkSize;
if (startIndex + chunkSize >= str.Length)
yield return str.Substring(startIndex);
else
yield return str.Substring(startIndex, chunkSize);
}
}
它涵盖了边缘情况。
List<string> SplitString(int chunk, string input)
{
List<string> list = new List<string>();
int cycles = input.Length / chunk;
if (input.Length % chunk != 0)
cycles++;
for (int i = 0; i < cycles; i++)
{
try
{
list.Add(input.Substring(i * chunk, chunk));
}
catch
{
list.Add(input.Substring(i * chunk));
}
}
return list;
}
List<string> chunks = new List<string>();
var longString = new string('s', 3000);
var chunkLength = 1273;
var ratio = (double)longString.Length / chunkLength;
var countOfChunks = Convert.ToByte(Math.Round(ratio, MidpointRounding.ToPositiveInfinity));
for (byte i = 0; i < countOfChunks; i++)
{
var remainingLength = longString.Length - chunkLength * i;
if (chunkLength > remainingLength)
chunks.Add(longString.Substring(i * chunkLength, remainingLength));
else
chunks.Add(longString.Substring(i * chunkLength, chunkLength));
}
这样写一行代码怎么样?
List<string> result = new List<string>(Regex.Split(target, @"(?<=\G.{4})", RegexOptions.Singleline));
对于这个正则表达式,最后一个块是否小于4个字符并不重要,因为它只查看它后面的字符。
我知道这不是最有效的解决方案,但我不得不把它扔出去。
static List<string> GetChunks(string value, int chunkLength)
{
var res = new List<string>();
int count = (value.Length / chunkLength) + (value.Length % chunkLength > 0 ? 1 : 0);
Enumerable.Range(0, count).ToList().ForEach(f => res.Add(value.Skip(f * chunkLength).Take(chunkLength).Select(z => z.ToString()).Aggregate((a,b) => a+b)));
return res;
}
demo