我正在寻找一个函数转换日期在一个时区到另一个。
它需要两个参数,
日期(格式为“2012/04/10 10:10:30 +0000”) 时区字符串("Asia/Jakarta")
时区字符串在http://en.wikipedia.org/wiki/Zone.tab中描述
有什么简单的方法吗?
我正在寻找一个函数转换日期在一个时区到另一个。
它需要两个参数,
日期(格式为“2012/04/10 10:10:30 +0000”) 时区字符串("Asia/Jakarta")
时区字符串在http://en.wikipedia.org/wiki/Zone.tab中描述
有什么简单的方法吗?
当前回答
我最近在Typescript中做了这个:
// fromTimezone example : Europe/Paris, toTimezone example: Europe/London
private calcTime( fromTimezone: string, toTimezone: string, dateFromTimezone: Date ): Date {
const dateToGetOffset = new Date( 2018, 5, 1, 12 );
const fromTimeString = dateToGetOffset.toLocaleTimeString( "en-UK", { timeZone: fromTimezone, hour12: false } );
const toTimeString = dateToGetOffset.toLocaleTimeString( "en-UK", { timeZone: toTimezone, hour12: false } );
const fromTimeHours: number = parseInt( fromTimeString.substr( 0, 2 ), 10 );
const toTimeHours: number = parseInt( toTimeString.substr( 0, 2 ), 10 );
const offset: number = fromTimeHours - toTimeHours;
// convert to msec
// add local time zone offset
// get UTC time in msec
const dateFromTimezoneUTC = Date.UTC( dateFromTimezone.getUTCFullYear(),
dateFromTimezone.getUTCMonth(),
dateFromTimezone.getUTCDate(),
dateFromTimezone.getUTCHours(),
dateFromTimezone.getUTCMinutes(),
dateFromTimezone.getUTCSeconds(),
);
// create new Date object for different city
// using supplied offset
const dateUTC = new Date( dateFromTimezoneUTC + ( 3600000 * offset ) );
// return time as a string
return dateUTC;
}
我使用“en-UK”格式,因为它是一个简单的。可能是"en-US"之类的。
如果第一个参数是本地时区,第二个参数是目标时区,它将返回一个具有正确偏移量的Date对象。
其他回答
如果你有一个时区偏移,你可以使用这个:
const timezoneDate = (timestamp: number, offsetInHours: number) => {
const shiftedTimestam = timestamp + offsetInHours * 3600000;
const shiftedDate = new Date(shiftedTimestam);
return {
date: shiftedDate.getUTCDate(),
hours: shiftedDate.getUTCHours(),
minutes: shiftedDate.getUTCMinutes(),
// ...other UTC methods
}
};
// Usage:
const newYorkDate = timezoneDate(Date.now(), -5);
console.log(
`It is ${newYorkDate.hours}:${newYorkDate.minutes} in NYC`
);
服务器有问题,选择gmt+0000标准时区,你可以在javascript中使用moment-timezone库来更改它
const moment = require("moment-timezone")
const dateNew = new Date()
const changeZone = moment(dateNew);
changeZone.tz("Asia/Karachi").format("ha z");
// here you can paste "your time zone string"
This is UTC date; converting UTC to IST timezone; let sampleArray = [ { date: "2022-12-22T19:16:26.803" }, { date: "2022-12-22T19:16:26.77" }, { date: "2022-12-22T19:16:26.737" }, { date: "2022-12-22T19:16:26.72" } ]; // Get all the results whose boolresult is 'true' // solution 1 sampleArray.map((element) => { let utcDate = new Date(element.date).getTime(); let dateIST = new Date(utcDate); dateIST.setHours(dateIST.getHours() + 5); dateIST.setMinutes(dateIST.getMinutes() + 30); element.date = dateIST; }); console.log("Result ==>>", sampleArray); // solution 2 sampleArray.map((element) => { element.date = new Date(element.date).toLocaleString("en-US", { timeZone: "Asia/Kolkata" }); }); console.log("Result 2==>>", sampleArray);
有一个npm模块叫做timezones。Json你可以使用它。它基本上由一个json文件和包含夏令时和偏移量信息的对象组成。
对于asia/jakarta,它可以返回这个对象:
{
"value": "SE Asia Standard Time",
"abbr": "SAST",
"offset": 7,
"isdst": false,
"text": "(UTC+07:00) Bangkok, Hanoi, Jakarta",
"utc": [
"Antarctica/Davis",
"Asia/Bangkok",
"Asia/Hovd",
"Asia/Jakarta",
"Asia/Phnom_Penh",
"Asia/Pontianak",
"Asia/Saigon",
"Asia/Vientiane",
"Etc/GMT-7",
"Indian/Christmas"
]
}
你可以在这里找到它:
https://github.com/dmfilipenko/timezones.json
https://www.npmjs.com/package/timezones.json
希望对大家有用
所有这些答案都有点多余,但这对我来说是有效的,可以获得具有特定小时偏移量的当前Date对象。
function hourToMs(hour) { return hour * 60 * 1000 * 60; } function minToMs(min) { return min * 60 * 1000; } function getCurrentDateByOffset(offset) { // Get the current timezone in milliseconds to reset back to GMT aka +0 let timezoneOffset = minToMs((new Date()).getTimezoneOffset()); // get the desired offset in milliseconds, invert the value because javascript is dum let desiredOffset = hourToMs(offset * -1); return new Date(Date.now() + timezoneOffset - desiredOffset); } // -6 hours is central timezone console.log("The time is: " + getCurrentDateByOffset(-6));