不能解决equal - to操作中“SQL_Latin1_General_CP1_CI_AS”和“Latin1_General_CI_AS”之间的排序冲突

我有下面的代码

SELECT tA.FieldName As [Field Name],
       COALESCE(tO_A.[desc], tO_B.[desc], tO_C.Name, tA.OldVAlue) AS [Old Value],
       COALESCE(tN_A.[desc], tN_B.[desc], tN_C.Name, tA.NewValue) AS [New Value],
       U.UserName AS [User Name],
       CONVERT(varchar, tA.ChangeDate) AS [Change Date] 
  FROM D tA
       JOIN 
       [DRTS].[dbo].[User] U 
         ON tA.UserID = U.UserID
       LEFT JOIN 
       A tO_A 
         on tA.FieldName = 'AID' 
        AND tA.oldValue = CONVERT(VARCHAR, tO_A.ID)
       LEFT JOIN 
       A tN_A 
         on tA.FieldName = 'AID' 
        AND tA.newValue = CONVERT(VARCHAR, tN_A.ID)
       LEFT JOIN 
       B tO_B 
         on tA.FieldName = 'BID' 
        AND tA.oldValue = CONVERT(VARCHAR, tO_B.ID)
       LEFT JOIN 
       B tN_B 
         on tA.FieldName = 'BID' 
        AND tA.newValue = CONVERT(VARCHAR, tN_B.ID)
       LEFT JOIN 
       C tO_C 
         on tA.FieldName = 'CID' 
        AND tA.oldValue = tO_C.Name
       LEFT JOIN 
       C tN_C 
         on tA.FieldName = 'CID' 
        AND tA.newValue = tN_C.Name
 WHERE U.Fullname = @SearchTerm
ORDER BY tA.ChangeDate

当运行代码时，我在添加表c的两个连接后，将错误粘贴在标题中。我认为这可能与我使用SQL Server 2008的事实有关，并在2005年的机器上恢复了这个db的副本。

当前回答

在where条件中添加collate SQL_Latin1_General_CP1_CI_AS

这对我很有用。

WHERE U.Fullname = @SearchTerm  collate SQL_Latin1_General_CP1_CI_AS

2018-06-08 17:40:59

其他回答

多亏了marc_s的回答，我解决了我最初的问题——受到启发，我想更进一步，发布一种一次转换整个表的方法——tsql脚本生成alter列语句:

DECLARE @tableName VARCHAR(MAX)
SET @tableName = 'affiliate'
--EXEC sp_columns @tableName
SELECT  'Alter table ' + @tableName + ' alter column ' + col.name
        + CASE ( col.user_type_id )
            WHEN 231
            THEN ' nvarchar(' + CAST(col.max_length / 2 AS VARCHAR) + ') '
          END + 'collate Latin1_General_CI_AS ' + CASE ( col.is_nullable )
                                                    WHEN 0 THEN ' not null'
                                                    WHEN 1 THEN ' null'
                                                  END
FROM    sys.columns col
WHERE   object_id = OBJECT_ID(@tableName)

得到: 修改myTable关联列(4000)，将Latin1_General_CI_AS为空

我承认对col.max_length / 2 -的需求感到困惑

2014-12-04 13:26:26

我以前有过类似的东西，我们发现两个表之间的排序是不同的。

检查它们是否相同。

2009-10-22 14:28:25

INSERT INTO eSSLSmartOfficeSource2.[dbo].DeviceLogs  (DeviceId,UserId,LogDate,UpdateFlag) 
SELECT DL1.DeviceId ,DL1.UserId COLLATE DATABASE_DEFAULT,DL1.LogDate 
,0 FROM eSSLSmartOffice.[dbo].DeviceLogs DL1 
WHERE  NOT EXISTS 
(SELECT DL2.DeviceId ,DL2.UserId COLLATE DATABASE_DEFAULT
,DL2.LogDate ,DL2.UpdateFlag 
FROM eSSLSmartOfficeSource2.[dbo].DeviceLogs DL2    
WHERE  DL1.DeviceId =DL2.DeviceId
 and DL1.UserId collate  Latin1_General_CS_AS=DL2.UserId collate  Latin1_General_CS_AS
  and DL1.LogDate =DL2.LogDate )

2018-03-08 06:34:25

如果这种情况发生在整个数据库中，那么最好像这样改变你的数据库排序规则:

USE master;  
GO  
ALTER DATABASE MyOptionsTest  
COLLATE << INSERT COLATION REQUIRED >> ;  
GO  

--Verify the collation setting.  
SELECT name, collation_name  
FROM sys.databases  
WHERE name = N'<< INSERT DATABASE NAME >>';  
GO

参考这里

2018-01-25 09:37:54

ALTER DATABASE test2            --put your database name here
COLLATE Latin1_General_CS_AS    --replace with the collation you need

2015-02-09 13:25:25

不能解决equal - to操作中“SQL_Latin1_General_CP1_CI_AS”和“Latin1_General_CI_AS”之间的排序冲突

推荐文章

最新文章

标签