我想在一个表中更新一个列，在其他表上进行连接，例如:
UPDATE table1 a
INNER JOIN table2 b ON a.commonfield = b.[common field]
SET a.CalculatedColumn= b.[Calculated Column]
WHERE
b.[common field]= a.commonfield
AND a.BatchNO = '110'
但它在抱怨:
警报170,15层，状态1,2号线 第2行:'a'附近的语法错误。
这里出了什么问题?
当前回答
使用MYSQL的用户
UPDATE table1 INNER JOIN table2 ON table2.id = table1.id SET table1.status = 0 WHERE table1.column = 20
其他回答
使用MYSQL的用户
UPDATE table1 INNER JOIN table2 ON table2.id = table1.id SET table1.status = 0 WHERE table1.column = 20
Try:
UPDATE table1
SET CalculatedColumn = ( SELECT [Calculated Column]
FROM table2
WHERE table1.commonfield = [common field])
WHERE BatchNO = '110'
UPDATE mytable
SET myfield = CASE other_field
WHEN 1 THEN 'value'
WHEN 2 THEN 'value'
WHEN 3 THEN 'value'
END
From mytable
Join otherTable on otherTable.id = mytable.id
Where othertable.somecolumn = '1234'
这里有更多的选择。
我发现将UPDATE转换为SELECT很有用，可以在更新之前获得我想要更新的作为测试的行。如果我能准确地选择我想要的行，我就可以更新我想要更新的行。
DECLARE @expense_report_id AS INT
SET @expense_report_id = 1027
--UPDATE expense_report_detail_distribution
--SET service_bill_id = 9
SELECT *
FROM expense_report_detail_distribution erdd
INNER JOIN expense_report_detail erd
INNER JOIN expense_report er
ON er.expense_report_id = erd.expense_report_id
ON erdd.expense_report_detail_id = erd.expense_report_detail_id
WHERE er.expense_report_id = @expense_report_id
试着这样做:
UPDATE a
SET a.CalculatedColumn= b.[Calculated Column]
FROM table1 a INNER JOIN table2 b ON a.commonfield = b.[common field]
WHERE a.BatchNO = '110'
