我想在一个表中更新一个列,在其他表上进行连接,例如:

UPDATE table1 a 
INNER JOIN table2 b ON a.commonfield = b.[common field] 
SET a.CalculatedColumn= b.[Calculated Column]
WHERE 
    b.[common field]= a.commonfield
AND a.BatchNO = '110'

但它在抱怨:

警报170,15层,状态1,2号线 第2行:'a'附近的语法错误。

这里出了什么问题?


当前回答

MERGE table1 T
   USING table2 S
      ON T.CommonField = S."Common Field"
         AND T.BatchNo = '110'
WHEN MATCHED THEN
   UPDATE
      SET CalculatedColumn = S."Calculated Column";

其他回答

Try:

UPDATE table1
SET CalculatedColumn = ( SELECT [Calculated Column] 
                         FROM table2 
                         WHERE table1.commonfield = [common field])
WHERE  BatchNO = '110'

我也有同样的问题。而且你不需要添加一个物理列。因为现在你必须维护它。 你能做的就是在select查询中添加一个泛型列:

EX:

select tb1.col1, tb1.col2, tb1.col3 ,
( 
select 'Match' from table2 as tbl2
where tbl1.col1 = tbl2.col1 and tab1.col2 = tbl2.col2
)  
from myTable as tbl1

试着这样做:

    UPDATE a 
    SET a.CalculatedColumn= b.[Calculated Column]
    FROM table1 a INNER JOIN table2 b ON a.commonfield = b.[common field] 
    WHERE a.BatchNO = '110'

另一种方法是使用MERGE

  ;WITH cteTable1(CalculatedColumn, CommonField)
  AS
  (
    select CalculatedColumn, CommonField from Table1 Where BatchNo = '110'
  )
  MERGE cteTable1 AS target
    USING (select "Calculated Column", "Common Field" FROM dbo.Table2) AS source ("Calculated Column", "Common Field")
    ON (target.CommonField = source."Common Field")
    WHEN MATCHED THEN 
        UPDATE SET target.CalculatedColumn = source."Calculated Column";

-Merge是SQL标准的一部分

-我也很确定内部连接更新是不确定的。 类似的问题,答案是这样说的 http://ask.sqlservercentral.com/questions/19089/updating-two-tables-using-single-query.html

我发现将UPDATE转换为SELECT很有用,可以在更新之前获得我想要更新的作为测试的行。如果我能准确地选择我想要的行,我就可以更新我想要更新的行。

DECLARE @expense_report_id AS INT
SET @expense_report_id = 1027

--UPDATE expense_report_detail_distribution
--SET service_bill_id = 9

SELECT *
FROM expense_report_detail_distribution erdd
INNER JOIN expense_report_detail erd
INNER JOIN expense_report er 
    ON er.expense_report_id = erd.expense_report_id 
    ON erdd.expense_report_detail_id = erd.expense_report_detail_id
WHERE er.expense_report_id = @expense_report_id