我对Bash中方括号、圆括号、花括号的用法以及它们的双形式和单形式之间的区别感到困惑。有明确的解释吗?


当前回答

关于如何使用括号对表达式进行分组和展开的其他信息: (它列在链接语法括号中)

这里有一些要点:

在子shell中分组命令:() (列表)

将当前shell中的命令分组:{} {列表;}

Test -返回一个表达式的二进制结果:[[]] [表达式]]

算术扩张 算术展开的格式是: $(表达式)

简单算术求值的格式是: (表达)

组合多个表达式 (表达式) (expr1 && expr2))

其他回答

test,[和[]之间的区别在BashFAQ中有详细的解释。 (注:链接中有很多例子供比较)

To cut a long story short: test implements the old, portable syntax of the command. In almost all shells (the oldest Bourne shells are the exception), [ is a synonym for test (but requires a final argument of ]). Although all modern shells have built-in implementations of [, there usually still is an external executable of that name, e.g. /bin/[. [[ is a new, improved version of it, and it is a keyword, not a program. This has beneficial effects on the ease of use, as shown below. [[ is understood by KornShell and BASH (e.g. 2.03), but not by the older POSIX or BourneShell.

结论是:

什么时候使用新的测试命令[[,什么时候使用旧的测试命令[? 如果要考虑到POSIX或BourneShell的可移植性/一致性,则应该考虑旧语法 被使用。如果脚本需要BASH、Zsh或KornShell, 新的语法通常更加灵活。

关于如何使用括号对表达式进行分组和展开的其他信息: (它列在链接语法括号中)

这里有一些要点:

在子shell中分组命令:() (列表)

将当前shell中的命令分组:{} {列表;}

Test -返回一个表达式的二进制结果:[[]] [表达式]]

算术扩张 算术展开的格式是: $(表达式)

简单算术求值的格式是: (表达)

组合多个表达式 (表达式) (expr1 && expr2))

括号

if [ CONDITION ]    Test construct  
if [[ CONDITION ]]  Extended test construct  
Array[1]=element1   Array initialization  
[a-z]               Range of characters within a Regular Expression
$[ expression ]     A non-standard & obsolete version of $(( expression )) [1]

[1] http://wiki.bash-hackers.org/scripting/obsolete

花括号

${variable}                             Parameter substitution  
${!variable}                            Indirect variable reference  
{ command1; command2; . . . commandN; } Block of code  
{string1,string2,string3,...}           Brace expansion  
{a..z}                                  Extended brace expansion  
{}                                      Text replacement, after find and xargs

括号

( command1; command2 )             Command group executed within a subshell  
Array=(element1 element2 element3) Array initialization  
result=$(COMMAND)                  Command substitution, new style  
>(COMMAND)                         Process substitution  
<(COMMAND)                         Process substitution 

双括号

(( var = 78 ))            Integer arithmetic   
var=$(( 20 + 5 ))         Integer arithmetic, with variable assignment   
(( var++ ))               C-style variable increment   
(( var-- ))               C-style variable decrement   
(( var0 = var1<98?9:21 )) C-style ternary operation
Truncate the contents of a variable

$ var="abcde"; echo ${var%d*}
abc

Make substitutions similar to sed

$ var="abcde"; echo ${var/de/12}
abc12

Use a default value

$ default="hello"; unset var; echo ${var:-$default}
hello

函数定义中的括号

括号()在函数定义中被使用:

function_name () { command1 ; command2 ; }

这就是在命令形参中也必须转义括号的原因:

$ echo (
bash: syntax error near unexpected token `newline'

$ echo \(
(

$ echo () { command echo The command echo was redefined. ; }
$ echo anything
The command echo was redefined.