我试图制作一个函数,将多个变量与一个整数进行比较,并输出一个三个字母的字符串。我想知道是否有办法将其翻译成Python。所以说:
x = 0
y = 1
z = 3
mylist = []
if x or y or z == 0:
mylist.append("c")
if x or y or z == 1:
mylist.append("d")
if x or y or z == 2:
mylist.append("e")
if x or y or z == 3:
mylist.append("f")
其将返回以下列表:
["c", "d", "f"]
要针对单个值测试多个变量,请执行以下操作:
将变量包装在集合对象中,例如{a,b,c}。使用in运算符测试值是否存储在任何变量中。如果值存储在至少一个变量中,in运算符将返回True。
# ✅ test multiple variables against single value using tuple
if 'a' in (a, b, c):
print('value is stored in at least one of the variables')
# ---------------------------------------------------------
# ✅ test multiple variables against single value using tuple
if 'a' in {a, b, c}:
print('value is stored in at least one of the variables')
# ---------------------------------------------------------
# ✅ test multiple variables against single value (OR operator chaining)
if a == 'a' or b == 'a' or c == 'a':
print('value is stored in at least one of the variables')
资料来源:https://bobbyhadz.com/blog/python-test-multiple-variables-against-single-value
如Martijn Pieters所述,正确且最快的格式是:
if 1 in {x, y, z}:
根据他的建议,您现在可以有单独的if语句,这样Python可以读取每个语句,无论前者是True还是False。例如:
if 0 in {x, y, z}:
mylist.append("c")
if 1 in {x, y, z}:
mylist.append("d")
if 2 in {x, y, z}:
mylist.append("e")
...
这会起作用,但如果你喜欢使用字典(看看我在那里做了什么),你可以通过创建一个将数字映射到你想要的字母的初始字典,然后使用for循环来清理这个问题:
num_to_letters = {0: "c", 1: "d", 2: "e", 3: "f"}
for number in num_to_letters:
if number in {x, y, z}:
mylist.append(num_to_letters[number])
我认为这会处理得更好:
my_dict = {0: "c", 1: "d", 2: "e", 3: "f"}
def validate(x, y, z):
for ele in [x, y, z]:
if ele in my_dict.keys():
return my_dict[ele]
输出:
print validate(0, 8, 9)
c
print validate(9, 8, 9)
None
print validate(9, 8, 2)
e