(前言:这个问题是关于2011年发布的ASP.NET MVC 3.0,而不是关于2019年发布的ASP.NETCore 3.0)
我想用asp.net mvc上传文件。如何使用html输入文件控件上载文件?
(前言:这个问题是关于2011年发布的ASP.NET MVC 3.0,而不是关于2019年发布的ASP.NETCore 3.0)
我想用asp.net mvc上传文件。如何使用html输入文件控件上载文件?
当前回答
在控制器中
if (MyModal.ImageFile != null)
{
MyModal.ImageURL = string.Format("{0}.{1}", Guid.NewGuid().ToString(), MyModal.ImageFile.FileName.Split('.').LastOrDefault());
if (MyModal.ImageFile != null)
{
var path = Path.Combine(Server.MapPath("~/Content/uploads/"), MyModal.ImageURL);
MyModal.ImageFile.SaveAs(path);
}
}
在视图中
<input type="hidden" value="" name="..."><input id="ImageFile" type="file" name="ImageFile" src="@Model.ImageURL">
在模态类中
public HttpPostedFileBase ImageFile { get; set; }
在项目的Content文件夹中创建上载文件夹
其他回答
提供完整的解决方案
首先在MVC视图中使用.CShtml中的输入
<input type="file" id="UploadImg" /></br>
<img id="imgPreview" height="200" width="200" />
现在调用Ajax调用
$("#UploadImg").change(function () {
var data = new FormData();
var files = $("#UploadImg").get(0).files;
if (files.length > 0) {
data.append("MyImages", files[0]);
}
$.ajax({
// url: "Controller/ActionMethod"
url: "/SignUp/UploadFile",
type: "POST",
processData: false,
contentType: false,
data: data,
success: function (response)
{
//code after success
$("#UploadPhoto").val(response);
$("#imgPreview").attr('src', '/Upload/' + response);
},
error: function (er) {
//alert(er);
}
});
});
控制器Json呼叫
[HttpGet]
public JsonResult UploadFile()
{
string _imgname = string.Empty;
if (System.Web.HttpContext.Current.Request.Files.AllKeys.Any())
{
var pic = System.Web.HttpContext.Current.Request.Files["MyImages"];
if (pic.ContentLength > 0)
{
var fileName = Path.GetFileName(pic.FileName);
var _ext = Path.GetExtension(pic.FileName);
_imgname = Guid.NewGuid().ToString();
var _comPath = Server.MapPath("/MyFolder") + _imgname + _ext;
_imgname = "img_" + _imgname + _ext;
ViewBag.Msg = _comPath;
var path = _comPath;
tblAssignment assign = new tblAssignment();
assign.Uploaded_Path = "/MyFolder" + _imgname + _ext;
// Saving Image in Original Mode
pic.SaveAs(path);
}
}
return Json(Convert.ToString(_imgname), JsonRequestBehavior.AllowGet);
}
如果有人想用Ajax上传多个文件,下面是我的文章在Asp.NetMVC中使用Ajax进行多文件上传
在视图中:
<form action="Categories/Upload" enctype="multipart/form-data" method="post">
<input type="file" name="Image">
<input type="submit" value="Save">
</form>
而控制器中的以下代码:
public ActionResult Upload()
{
foreach (string file in Request.Files)
{
var hpf = this.Request.Files[file];
if (hpf.ContentLength == 0)
{
continue;
}
string savedFileName = Path.Combine(
AppDomain.CurrentDomain.BaseDirectory, "PutYourUploadDirectoryHere");
savedFileName = Path.Combine(savedFileName, Path.GetFileName(hpf.FileName));
hpf.SaveAs(savedFileName);
}
...
}
public ActionResult FileUpload(upload mRegister) {
//Check server side validation using data annotation
if (ModelState.IsValid) {
//TO:DO
var fileName = Path.GetFileName(mRegister.file.FileName);
var path = Path.Combine(Server.MapPath("~/Content/Upload"), fileName);
mRegister.file.SaveAs(path);
ViewBag.Message = "File has been uploaded successfully";
ModelState.Clear();
}
return View();
}
Html:
@using (Html.BeginForm("StoreMyCompany", "MyCompany", FormMethod.Post, new { id = "formMyCompany", enctype = "multipart/form-data" }))
{
<div class="form-group">
@Html.LabelFor(model => model.modelMyCompany.Logo, htmlAttributes: new { @class = "control-label col-md-3" })
<div class="col-md-6">
<input type="file" name="Logo" id="fileUpload" accept=".png,.jpg,.jpeg,.gif,.tif" />
</div>
</div>
<br />
<div class="form-group">
<div class="col-md-offset-3 col-md-6">
<input type="submit" value="Save" class="btn btn-success" />
</div>
</div>
}
背后代码:
public ActionResult StoreMyCompany([Bind(Exclude = "Logo")]MyCompanyVM model)
{
try
{
byte[] imageData = null;
if (Request.Files.Count > 0)
{
HttpPostedFileBase objFiles = Request.Files["Logo"];
using (var binaryReader = new BinaryReader(objFiles.InputStream))
{
imageData = binaryReader.ReadBytes(objFiles.ContentLength);
}
}
if (imageData != null && imageData.Length > 0)
{
//Your code
}
dbo.SaveChanges();
return RedirectToAction("MyCompany", "Home");
}
catch (Exception ex)
{
Utility.LogError(ex);
}
return View();
}