This is what I do when testing to make sure an exception has been thrown

    
    //when
    final var tripConsumer = new BusTripConsumer(inputStream);
    final Executable executable = () -> tripConsumer.deserialiseTripData();

    //then
    assertThrows(IllegalArgumentException.class, executable);

我的解决方案:

    protected <T extends Throwable> void assertExpectedException(ThrowingRunnable methodExpectedToFail, Class<T> expectedThrowableClass,
        String expectedMessage) {
    T exception = assertThrows(expectedThrowableClass, methodExpectedToFail);
    assertEquals(expectedMessage, exception.getMessage());
}

你可以这样称呼它:

    assertExpectedException(() -> {
        carService.findById(id);
    }, IllegalArgumentException.class, "invalid id");

This is what I do when testing to make sure an exception has been thrown

    
    //when
    final var tripConsumer = new BusTripConsumer(inputStream);
    final Executable executable = () -> tripConsumer.deserialiseTripData();

    //then
    assertThrows(IllegalArgumentException.class, executable);

实际上，我认为这个特殊例子的文档中有一个错误。预期的方法是expectThrows

public static void assertThrows(
public static <T extends Throwable> T expectThrows(

我认为这是一个更简单的例子

List<String> emptyList = new ArrayList<>();
Optional<String> opt2 = emptyList.stream().findFirst();
assertThrows(NoSuchElementException.class, () -> opt2.get());

在包含空数组列表的可选对象上调用get()将抛出NoSuchElementException异常。assertThrows声明预期的异常并提供lambda提供者(不接受参数并返回值)。

感谢@prime的回答，我希望能详细说明。

这里有一个简单的方法。

@Test
void exceptionTest() {

   try{
        model.someMethod("invalidInput");
        fail("Exception Expected!");
   }
   catch(SpecificException e){

        assertTrue(true);
   }
   catch(Exception e){
        fail("wrong exception thrown");
   }

}

它只有在抛出您期望的异常时才会成功。