我想检查设备的iOS版本是否大于3.1.3 我尝试了以下方法:
[[UIDevice currentDevice].systemVersion floatValue]
但是不管用,我只想要一个:
if (version > 3.1.3) { }
我怎样才能做到这一点呢?
我想检查设备的iOS版本是否大于3.1.3 我尝试了以下方法:
[[UIDevice currentDevice].systemVersion floatValue]
但是不管用,我只想要一个:
if (version > 3.1.3) { }
我怎样才能做到这一点呢?
当前回答
我的解决方案是向您的实用程序类(提示提示)添加一个实用程序方法来解析系统版本并手动补偿浮点数排序。
此外,这段代码相当简单,所以我希望它能帮助一些新手。简单地传入一个目标浮点数,然后返回BOOL类型。
在你的共享类中这样声明它:
(+) (BOOL) iOSMeetsOrExceedsVersion:(float)targetVersion;
这样叫它:
BOOL shouldBranch = [SharedClass iOSMeetsOrExceedsVersion:5.0101];
(+) (BOOL) iOSMeetsOrExceedsVersion:(float)targetVersion {
/*
Note: the incoming targetVersion should use 2 digits for each subVersion --
example 5.01 for v5.1, 5.11 for v5.11 (aka subversions above 9), 5.0101 for v5.1.1, etc.
*/
// Logic: as a string, system version may have more than 2 segments (example: 5.1.1)
// so, a direct conversion to a float may return an invalid number
// instead, parse each part directly
NSArray *sysVersion = [[UIDevice currentDevice].systemVersion componentsSeparatedByString:@"."];
float floatVersion = [[sysVersion objectAtIndex:0] floatValue];
if (sysVersion.count > 1) {
NSString* subVersion = [sysVersion objectAtIndex:1];
if (subVersion.length == 1)
floatVersion += ([[sysVersion objectAtIndex:1] floatValue] *0.01);
else
floatVersion += ([[sysVersion objectAtIndex:1] floatValue] *0.10);
}
if (sysVersion.count > 2) {
NSString* subVersion = [sysVersion objectAtIndex:2];
if (subVersion.length == 1)
floatVersion += ([[sysVersion objectAtIndex:2] floatValue] *0.0001);
else
floatVersion += ([[sysVersion objectAtIndex:2] floatValue] *0.0010);
}
if (floatVersion >= targetVersion)
return TRUE;
// else
return FALSE;
}
其他回答
使用nv-ios-version项目(Apache License, Version 2.0)中包含的Version类,很容易获取和比较iOS版本。下面的示例代码转储iOS版本,并检查版本是否大于或等于6.0。
// Get the system version of iOS at runtime.
NSString *versionString = [[UIDevice currentDevice] systemVersion];
// Convert the version string to a Version instance.
Version *version = [Version versionWithString:versionString];
// Dump the major, minor and micro version numbers.
NSLog(@"version = [%d, %d, %d]",
version.major, version.minor, version.micro);
// Check whether the version is greater than or equal to 6.0.
if ([version isGreaterThanOrEqualToMajor:6 minor:0])
{
// The iOS version is greater than or equal to 6.0.
}
// Another way to check whether iOS version is
// greater than or equal to 6.0.
if (6 <= version.major)
{
// The iOS version is greater than or equal to 6.0.
}
项目页面:nv-ios-version TakahikoKawasaki / nv-ios-version
博客:获取并比较iOS版本在运行时与版本类 获取并比较iOS版本在运行时与版本类
/*
* System Versioning Preprocessor Macros
*/
#define SYSTEM_VERSION_EQUAL_TO(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] == NSOrderedSame)
#define SYSTEM_VERSION_GREATER_THAN(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] == NSOrderedDescending)
#define SYSTEM_VERSION_GREATER_THAN_OR_EQUAL_TO(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] != NSOrderedAscending)
#define SYSTEM_VERSION_LESS_THAN(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] == NSOrderedAscending)
#define SYSTEM_VERSION_LESS_THAN_OR_EQUAL_TO(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] != NSOrderedDescending)
/*
* Usage
*/
if (SYSTEM_VERSION_LESS_THAN(@"4.0")) {
...
}
if (SYSTEM_VERSION_GREATER_THAN_OR_EQUAL_TO(@"3.1.1")) {
...
}
试试下面的代码:
NSString *versionString = [[UIDevice currentDevice] systemVersion];
快速的例子,实际工作:
switch UIDevice.currentDevice().systemVersion.compare("8.0.0", options: NSStringCompareOptions.NumericSearch) {
case .OrderedSame, .OrderedDescending:
println("iOS >= 8.0")
case .OrderedAscending:
println("iOS < 8.0")
}
不要使用NSProcessInfo,因为它在8.0下不能工作,所以它在2016年之前几乎没用
我知道这是一个老问题,但是应该有人在available .h中提到编译时宏。这里的所有其他方法都是运行时解决方案,不能在头文件、类类别或ivar定义中工作。
对于这些情况,使用
#if __IPHONE_OS_VERSION_MAX_ALLOWED >= __IPHONE_14_0 && defined(__IPHONE_14_0)
// iOS 14+ code here
#else
// Pre iOS 14 code here
#endif
不要这样回答