我想检查设备的iOS版本是否大于3.1.3 我尝试了以下方法:
[[UIDevice currentDevice].systemVersion floatValue]
但是不管用,我只想要一个:
if (version > 3.1.3) { }
我怎样才能做到这一点呢?
我想检查设备的iOS版本是否大于3.1.3 我尝试了以下方法:
[[UIDevice currentDevice].systemVersion floatValue]
但是不管用,我只想要一个:
if (version > 3.1.3) { }
我怎样才能做到这一点呢?
当前回答
试试下面的代码:
NSString *versionString = [[UIDevice currentDevice] systemVersion];
其他回答
+(BOOL)doesSystemVersionMeetRequirement:(NSString *)minRequirement{
// eg NSString *reqSysVer = @"4.0";
NSString *currSysVer = [[UIDevice currentDevice] systemVersion];
if ([currSysVer compare:minRequirement options:NSNumericSearch] != NSOrderedAscending)
{
return YES;
}else{
return NO;
}
}
在您的项目中添加以下Swift代码,并轻松访问iOS版本和设备等信息。
class DeviceInfo: NSObject {
struct ScreenSize
{
static let SCREEN_WIDTH = UIScreen.main.bounds.size.width
static let SCREEN_HEIGHT = UIScreen.main.bounds.size.height
static let SCREEN_MAX_LENGTH = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
static let SCREEN_MIN_LENGTH = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}
struct DeviceType
{
static let IS_IPHONE_4_OR_LESS = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
static let IS_IPHONE_6 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH >= 667.0
static let IS_IPHONE_6P = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
static let IS_IPHONE_X = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 812.0
static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
static let IS_IPAD_PRO = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1366.0
}
struct VersionType{
static let SYS_VERSION_FLOAT = (UIDevice.current.systemVersion as NSString).floatValue
static let iOS7 = (VersionType.SYS_VERSION_FLOAT < 8.0 && VersionType.SYS_VERSION_FLOAT >= 7.0)
static let iOS8 = (VersionType.SYS_VERSION_FLOAT >= 8.0 && VersionType.SYS_VERSION_FLOAT < 9.0)
static let iOS9 = (VersionType.SYS_VERSION_FLOAT >= 9.0 && VersionType.SYS_VERSION_FLOAT < 10.0)
static let iOS10 = (VersionType.SYS_VERSION_FLOAT >= 9.0 && VersionType.SYS_VERSION_FLOAT < 11.0)
}
}
#define IsIOS8 (NSFoundationVersionNumber > NSFoundationVersionNumber_iOS_7_1)
作为yasimturks解决方案的一种变体,我定义了一个函数和一些枚举值,而不是五个宏。我觉得它更优雅,但那是个人品味的问题。
用法:
if (systemVersion(LessThan, @"5.0")) ...
. h文件:
typedef enum {
LessThan,
LessOrEqual,
Equal,
GreaterOrEqual,
GreaterThan,
NotEqual
} Comparison;
BOOL systemVersion(Comparison test, NSString* version);
m文件:
BOOL systemVersion(Comparison test, NSString* version) {
NSComparisonResult result = [[[UIDevice currentDevice] systemVersion] compare: version options: NSNumericSearch];
switch (test) {
case LessThan: return result == NSOrderedAscending;
case LessOrEqual: return result != NSOrderedDescending;
case Equal: return result == NSOrderedSame;
case GreaterOrEqual: return result != NSOrderedAscending;
case GreaterThan: return result == NSOrderedDescending;
case NotEqual: return result != NSOrderedSame;
}
}
你应该在名称中添加应用程序的前缀,尤其是比较类型。
if (floor(NSFoundationVersionNumber) > NSFoundationVersionNumber_iOS_6_1) {
// Your code here
}
当然,其中NSFoundationVersionNumber_iOS_6_1必须更改为by适用于您要检查的iOS版本。我现在所写的内容在测试设备是否运行iOS7或之前的版本时可能会经常用到。