我想检查设备的iOS版本是否大于3.1.3 我尝试了以下方法:

[[UIDevice currentDevice].systemVersion floatValue]

但是不管用,我只想要一个:

if (version > 3.1.3) { }

我怎样才能做到这一点呢?


当前回答

使用swift Forget [[UIDevice currentDevice] systemVersion]和NSFoundationVersionNumber检查系统版本的新方法。

我们可以使用NSProcessInfo -isOperatingSystemAtLeastVersion

     import Foundation

     let yosemite = NSOperatingSystemVersion(majorVersion: 10, minorVersion: 10, patchVersion: 0)
     NSProcessInfo().isOperatingSystemAtLeastVersion(yosemite) // false

其他回答

#define _kisiOS7 ([[[UIDevice currentDevice] systemVersion] floatValue] >= 7.0)

if (_kisiOS7) {
            NSLog(@"iOS7 or greater")
} 
else {
           NSLog(@"Less than iOS7");
}

使用nv-ios-version项目(Apache License, Version 2.0)中包含的Version类,很容易获取和比较iOS版本。下面的示例代码转储iOS版本,并检查版本是否大于或等于6.0。

// Get the system version of iOS at runtime.
NSString *versionString = [[UIDevice currentDevice] systemVersion];

// Convert the version string to a Version instance.
Version *version = [Version versionWithString:versionString];

// Dump the major, minor and micro version numbers.
NSLog(@"version = [%d, %d, %d]",
    version.major, version.minor, version.micro);

// Check whether the version is greater than or equal to 6.0.
if ([version isGreaterThanOrEqualToMajor:6 minor:0])
{
    // The iOS version is greater than or equal to 6.0.
}

// Another way to check whether iOS version is
// greater than or equal to 6.0.
if (6 <= version.major)
{
    // The iOS version is greater than or equal to 6.0.
}

项目页面:nv-ios-version TakahikoKawasaki / nv-ios-version

博客:获取并比较iOS版本在运行时与版本类 获取并比较iOS版本在运行时与版本类

开始Xcode 9,在Objective-C中:

if (@available(iOS 11, *)) {
    // iOS 11 (or newer) ObjC code
} else {
    // iOS 10 or older code
}

开始Xcode 7,在Swift中:

if #available(iOS 11, *) {
    // iOS 11 (or newer) Swift code
} else {
    // iOS 10 or older code
}

对于版本,您可以指定MAJOR、MINOR或PATCH(参见http://semver.org/的定义)。例子:

iOS 11和iOS 11.0是相同的最小版本 iOS 10, iOS 10.3, iOS 10.3.1是不同的最小版本

您可以为这些系统中的任何一个输入值:

iOS, macOS, watchOS, tvOS

来自我的一个豆荚的真实案例:

if #available(iOS 10.0, tvOS 10.0, *) {
    // iOS 10+ and tvOS 10+ Swift code
} else {
    // iOS 9 and tvOS 9 older code
}

文档

float deviceOSVersion = [[[UIDevice currentDevice] systemVersion] floatValue];
float versionToBeCompared = 3.1.3; //(For Example in your case)

if(deviceOSVersion < versionToBeCompared)
   //Do whatever you need to do. Device version is lesser than 3.1.3(in your case)
else 
   //Device version should be either equal to the version you specified or above

我的解决方案是向您的实用程序类(提示提示)添加一个实用程序方法来解析系统版本并手动补偿浮点数排序。

此外,这段代码相当简单,所以我希望它能帮助一些新手。简单地传入一个目标浮点数,然后返回BOOL类型。

在你的共享类中这样声明它:

(+) (BOOL) iOSMeetsOrExceedsVersion:(float)targetVersion;

这样叫它:

BOOL shouldBranch = [SharedClass iOSMeetsOrExceedsVersion:5.0101];

(+) (BOOL) iOSMeetsOrExceedsVersion:(float)targetVersion {

/*
 Note: the incoming targetVersion should use 2 digits for each subVersion --

 example 5.01 for v5.1, 5.11 for v5.11 (aka subversions above 9), 5.0101 for v5.1.1, etc.
*/

// Logic: as a string, system version may have more than 2 segments (example: 5.1.1)
// so, a direct conversion to a float may return an invalid number
// instead, parse each part directly

NSArray *sysVersion = [[UIDevice currentDevice].systemVersion componentsSeparatedByString:@"."];
float floatVersion = [[sysVersion objectAtIndex:0] floatValue];
if (sysVersion.count > 1) {
    NSString* subVersion = [sysVersion objectAtIndex:1];
    if (subVersion.length == 1)
        floatVersion += ([[sysVersion objectAtIndex:1] floatValue] *0.01);
    else
        floatVersion += ([[sysVersion objectAtIndex:1] floatValue] *0.10);
}
if (sysVersion.count > 2) {
    NSString* subVersion = [sysVersion objectAtIndex:2];
    if (subVersion.length == 1)
        floatVersion += ([[sysVersion objectAtIndex:2] floatValue] *0.0001);
    else
        floatVersion += ([[sysVersion objectAtIndex:2] floatValue] *0.0010);
}

if (floatVersion  >= targetVersion) 
    return TRUE;

// else
return FALSE;
 }