我如何检查一个数字是正的或负的c# ?


当前回答

过分了!

public static class AwesomeExtensions
{
    public static bool IsPositive(this int number)
    {
        return number > 0;
    }

    public static bool IsNegative(this int number)
    {
        return number < 0;
    }

    public static bool IsZero(this int number)
    {
        return number == 0;
    }

    public static bool IsAwesome(this int number)
    {
        return IsNegative(number) && IsPositive(number) && IsZero(number);
    }
}

其他回答

过分了!

public static class AwesomeExtensions
{
    public static bool IsPositive(this int number)
    {
        return number > 0;
    }

    public static bool IsNegative(this int number)
    {
        return number < 0;
    }

    public static bool IsZero(this int number)
    {
        return number == 0;
    }

    public static bool IsAwesome(this int number)
    {
        return IsNegative(number) && IsPositive(number) && IsZero(number);
    }
}
bool positive = number > 0;
bool negative = number < 0;

你只需要比较是否值和它的绝对值相等:

if (value == Math.abs(value))
    return "Positif"
else return "Negatif"
bool isNegative(int n) {
  int i;
  for (i = 0; i <= Int32.MaxValue; i++) {
    if (n == i) 
      return false;
  }
  return true;
}
public static bool IsNegative<T>(T value)
   where T : struct, IComparable<T>
{
    return value.CompareTo(default(T)) < 0;
}