我如何退出JavaScript脚本,就像PHP的退出或死亡?我知道这不是最好的编程实践,但我需要这样做。
当前回答
我使用return语句而不是throw,因为throw在控制台给出错误。最好的办法是检查情况
if(condition){
return //whatever you want to return
}
这只是从这一行停止程序的执行,而不是在控制台中给出任何错误。
其他回答
在大多数情况下不适用,但我有很多异步脚本在浏览器中运行,作为一个hack我做
window.reload();
停止一切。
这段代码将停止当前窗口中所有javascript的执行:
(,);
例子
console.log('READY!'); setTimeout(()=>{ /* animation call */ div.className = "anim"; console.log('SET!'); setTimeout(()=>{ setTimeout(()=>{ console.log('this code will never be executed'); },1000); console.log('GO!'); /* BOMB */ for(;;); console.log('this code will never be executed'); },1000); },1000); #div { position: fixed; height: 1rem; width: 1rem; left: 0rem; top: 0rem; transition: all 5s; background: red; } /* this <div> will never reached the right bottom corner */ #div.anim { left: calc(100vw - 1rem); top: calc(100vh - 1rem); } <div id="div"></div>
JavaScript相当于PHP的die。顺便说一句,它只是调用exit()(谢谢splattne):
function exit( status ) {
// http://kevin.vanzonneveld.net
// + original by: Brett Zamir (http://brettz9.blogspot.com)
// + input by: Paul
// + bugfixed by: Hyam Singer (http://www.impact-computing.com/)
// + improved by: Philip Peterson
// + bugfixed by: Brett Zamir (http://brettz9.blogspot.com)
// % note 1: Should be considered expirimental. Please comment on this function.
// * example 1: exit();
// * returns 1: null
var i;
if (typeof status === 'string') {
alert(status);
}
window.addEventListener('error', function (e) {e.preventDefault();e.stopPropagation();}, false);
var handlers = [
'copy', 'cut', 'paste',
'beforeunload', 'blur', 'change', 'click', 'contextmenu', 'dblclick', 'focus', 'keydown', 'keypress', 'keyup', 'mousedown', 'mousemove', 'mouseout', 'mouseover', 'mouseup', 'resize', 'scroll',
'DOMNodeInserted', 'DOMNodeRemoved', 'DOMNodeRemovedFromDocument', 'DOMNodeInsertedIntoDocument', 'DOMAttrModified', 'DOMCharacterDataModified', 'DOMElementNameChanged', 'DOMAttributeNameChanged', 'DOMActivate', 'DOMFocusIn', 'DOMFocusOut', 'online', 'offline', 'textInput',
'abort', 'close', 'dragdrop', 'load', 'paint', 'reset', 'select', 'submit', 'unload'
];
function stopPropagation (e) {
e.stopPropagation();
// e.preventDefault(); // Stop for the form controls, etc., too?
}
for (i=0; i < handlers.length; i++) {
window.addEventListener(handlers[i], function (e) {stopPropagation(e);}, true);
}
if (window.stop) {
window.stop();
}
throw '';
}
在我的例子中,我使用window.stop。
window.stop()在当前浏览上下文中停止进一步的资源加载,相当于浏览器中的'stop'按钮。 由于脚本的执行方式不同,此方法不能中断其父文档的加载,但它将停止其父文档的图像、新窗口和其他仍在加载的对象。 用法:window.stop (); (源)
If you're looking for a way to forcibly terminate execution of all Javascript on a page, I'm not sure there is an officially sanctioned way to do that - it seems like the kind of thing that might be a security risk (although to be honest, I can't think of how it would be off the top of my head). Normally in Javascript when you want your code to stop running, you just return from whatever function is executing. (The return statement is optional if it's the last thing in the function and the function shouldn't return a value) If there's some reason returning isn't good enough for you, you should probably edit more detail into the question as to why you think you need it and perhaps someone can offer an alternate solution.
注意,在实践中,大多数浏览器的Javascript解释器在遇到错误时会简单地停止运行当前脚本。所以你可以做一些事情,比如访问一个未设置变量的属性:
function exit() {
p.blah();
}
它可能会中止脚本。但你不应该指望它,因为它根本不是标准的,而且它看起来真的是一个糟糕的做法。
编辑:好吧,也许这不是一个很好的答案Ólafur的光。尽管他链接到的die()函数基本上实现了我的第二段,即它只是抛出一个错误。
推荐文章
- 错误:'types'只能在.ts文件中使用- Visual Studio Code使用@ts-check
- React-Native:应用程序未注册错误
- LoDash:从对象属性数组中获取值数组
- src和dist文件夹的作用是什么?
- jQuery UI对话框-缺少关闭图标
- 如何使用AngularJS获取url参数
- 将RGB转换为白色的RGBA
- 如何将“camelCase”转换为“Camel Case”?
- 我们可以在另一个JS文件中调用用一个JavaScript编写的函数吗?
- 如何使用JavaScript重新加载ReCaptcha ?
- jQuery。由于转义了JSON中的单引号,parseJSON抛出“无效JSON”错误
- 在JavaScript关联数组中动态创建键
- ReactJS和公共文件夹中的图像
- 在React Native中使用Fetch授权头
- 为什么我的球(物体)没有缩小/消失?