我如何退出JavaScript脚本,就像PHP的退出或死亡?我知道这不是最好的编程实践,但我需要这样做。
当前回答
这段代码将停止当前窗口中所有javascript的执行:
(,);
例子
console.log('READY!'); setTimeout(()=>{ /* animation call */ div.className = "anim"; console.log('SET!'); setTimeout(()=>{ setTimeout(()=>{ console.log('this code will never be executed'); },1000); console.log('GO!'); /* BOMB */ for(;;); console.log('this code will never be executed'); },1000); },1000); #div { position: fixed; height: 1rem; width: 1rem; left: 0rem; top: 0rem; transition: all 5s; background: red; } /* this <div> will never reached the right bottom corner */ #div.anim { left: calc(100vw - 1rem); top: calc(100vh - 1rem); } <div id="div"></div>
其他回答
简单地创建一个BOOL条件, 这里不需要复杂的代码。
即使你把它变成true/或多次, 它会给你一条解,而不是多条解 基本上就是这么简单。
JavaScript相当于PHP的die。顺便说一句,它只是调用exit()(谢谢splattne):
function exit( status ) {
// http://kevin.vanzonneveld.net
// + original by: Brett Zamir (http://brettz9.blogspot.com)
// + input by: Paul
// + bugfixed by: Hyam Singer (http://www.impact-computing.com/)
// + improved by: Philip Peterson
// + bugfixed by: Brett Zamir (http://brettz9.blogspot.com)
// % note 1: Should be considered expirimental. Please comment on this function.
// * example 1: exit();
// * returns 1: null
var i;
if (typeof status === 'string') {
alert(status);
}
window.addEventListener('error', function (e) {e.preventDefault();e.stopPropagation();}, false);
var handlers = [
'copy', 'cut', 'paste',
'beforeunload', 'blur', 'change', 'click', 'contextmenu', 'dblclick', 'focus', 'keydown', 'keypress', 'keyup', 'mousedown', 'mousemove', 'mouseout', 'mouseover', 'mouseup', 'resize', 'scroll',
'DOMNodeInserted', 'DOMNodeRemoved', 'DOMNodeRemovedFromDocument', 'DOMNodeInsertedIntoDocument', 'DOMAttrModified', 'DOMCharacterDataModified', 'DOMElementNameChanged', 'DOMAttributeNameChanged', 'DOMActivate', 'DOMFocusIn', 'DOMFocusOut', 'online', 'offline', 'textInput',
'abort', 'close', 'dragdrop', 'load', 'paint', 'reset', 'select', 'submit', 'unload'
];
function stopPropagation (e) {
e.stopPropagation();
// e.preventDefault(); // Stop for the form controls, etc., too?
}
for (i=0; i < handlers.length; i++) {
window.addEventListener(handlers[i], function (e) {stopPropagation(e);}, true);
}
if (window.stop) {
window.stop();
}
throw '';
}
If you're looking for a way to forcibly terminate execution of all Javascript on a page, I'm not sure there is an officially sanctioned way to do that - it seems like the kind of thing that might be a security risk (although to be honest, I can't think of how it would be off the top of my head). Normally in Javascript when you want your code to stop running, you just return from whatever function is executing. (The return statement is optional if it's the last thing in the function and the function shouldn't return a value) If there's some reason returning isn't good enough for you, you should probably edit more detail into the question as to why you think you need it and perhaps someone can offer an alternate solution.
注意,在实践中,大多数浏览器的Javascript解释器在遇到错误时会简单地停止运行当前脚本。所以你可以做一些事情,比如访问一个未设置变量的属性:
function exit() {
p.blah();
}
它可能会中止脚本。但你不应该指望它,因为它根本不是标准的,而且它看起来真的是一个糟糕的做法。
编辑:好吧,也许这不是一个很好的答案Ólafur的光。尽管他链接到的die()函数基本上实现了我的第二段,即它只是抛出一个错误。
我想这个问题已经有答案了,点击这里了解更多信息。下面是它发布的简短答案。
throw new Error("Stop script");
您也可以使用您的浏览器添加断点,每个浏览器都是类似的,检查以下信息为您的浏览器。
为Chrome断点信息点击这里 有关Firefox断点信息,请点击这里 有关资源管理器断点信息,请单击 有关Safari断点信息,请点击这里
在我的例子中,我使用window.stop。
window.stop()在当前浏览上下文中停止进一步的资源加载,相当于浏览器中的'stop'按钮。 由于脚本的执行方式不同,此方法不能中断其父文档的加载,但它将停止其父文档的图像、新窗口和其他仍在加载的对象。 用法:window.stop (); (源)
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