我如何退出JavaScript脚本,就像PHP的退出或死亡?我知道这不是最好的编程实践,但我需要这样做。


当前回答

在大多数情况下不适用,但我有很多异步脚本在浏览器中运行,作为一个hack我做

window.reload();

停止一切。

其他回答

我使用ibroker和容易地设法停止脚本

stopScript();

If you're looking for a way to forcibly terminate execution of all Javascript on a page, I'm not sure there is an officially sanctioned way to do that - it seems like the kind of thing that might be a security risk (although to be honest, I can't think of how it would be off the top of my head). Normally in Javascript when you want your code to stop running, you just return from whatever function is executing. (The return statement is optional if it's the last thing in the function and the function shouldn't return a value) If there's some reason returning isn't good enough for you, you should probably edit more detail into the question as to why you think you need it and perhaps someone can offer an alternate solution.

注意,在实践中,大多数浏览器的Javascript解释器在遇到错误时会简单地停止运行当前脚本。所以你可以做一些事情,比如访问一个未设置变量的属性:

function exit() {
    p.blah();
}

它可能会中止脚本。但你不应该指望它,因为它根本不是标准的,而且它看起来真的是一个糟糕的做法。

编辑:好吧,也许这不是一个很好的答案Ólafur的光。尽管他链接到的die()函数基本上实现了我的第二段,即它只是抛出一个错误。

放置调试器;关键字,在你想要停止执行的JavaScript代码。然后打开您喜欢的浏览器的开发人员工具并重新加载页面。现在它应该自动暂停。打开工具的Sources部分:调试器;关键字高亮显示,您可以选择恢复脚本执行。

我希望这能有所帮助。

更多信息请浏览:

https://developer.mozilla.org/de/docs/Tools/Debugger http://www.w3schools.com/js/js_debugging.asp

这个小函数非常接近于模仿PHP的exit()。与其他解决方案一样,不要添加任何其他解决方案。

function exit(Msg)
    {
    Msg=Msg?'*** '+Msg:'';
    if (Msg) alert(Msg);
    throw new Error();
    } // exit

如果你只是想停止执行更多的代码而不“抛出”任何错误,你可以暂时覆盖window。如cross-exit所示:

function exit(code) {
    const prevOnError = window.onerror
    window.onerror = () => {
        window.onerror = prevOnError
        return true
    }

    throw new Error(`Script termination with code ${code || 0}.`)
}

console.log("This message is logged.");
exit();
console.log("This message isn't logged.");