我如何退出JavaScript脚本,就像PHP的退出或死亡?我知道这不是最好的编程实践,但我需要这样做。


当前回答

Javascript可以在devtools中禁用:ctrl+shift+j跟随cltf+shift+p,然后输入disable Javascript

上述可能的选项:

window.stop(); // equivalent to the 'stop' button in the browser
debugger; // debugs
for(;;); // crashes your browser
window.location.reload(); // reloads current page

如果页面已加载,而你不想调试崩溃或重新加载:

throw new Error();

此外,清除所有超时

var id = window.setTimeout(function() {}, 0);
while (id--) {
    window.clearTimeout(id);
}

中止DOM - XMLHttpRequest

$.xhrPool = [];
$.xhrPool.abortAll = function() {
    $(this).each(function(i, jqXHR) { 
        jqXHR.abort();  
        $.xhrPool.splice(i, 1); 
    });
}
$.ajaxSetup({
    beforeSend: function(jqXHR) { $.xhrPool.push(jqXHR); },
    complete: function(jqXHR) {
        var i = $.xhrPool.indexOf(jqXHR);
        if (i > -1) $.xhrPool.splice(i, 1); 
    }
});

删除所有事件监听器,包括内联监听器

$("*").prop("onclick", null).off();

这将删除脚本并重新创建没有事件的元素

$('script').remove();
$('*').each(function(){
    $(this).replaceWith($(this).clone());   
});

如果网页上没有jQuery,则复制粘贴源代码到控制台。

可能还有其他的东西。请在评论中告诉我。

其他回答

在大多数情况下不适用,但我有很多异步脚本在浏览器中运行,作为一个hack我做

window.reload();

停止一切。

Javascript可以在devtools中禁用:ctrl+shift+j跟随cltf+shift+p,然后输入disable Javascript

上述可能的选项:

window.stop(); // equivalent to the 'stop' button in the browser
debugger; // debugs
for(;;); // crashes your browser
window.location.reload(); // reloads current page

如果页面已加载,而你不想调试崩溃或重新加载:

throw new Error();

此外,清除所有超时

var id = window.setTimeout(function() {}, 0);
while (id--) {
    window.clearTimeout(id);
}

中止DOM - XMLHttpRequest

$.xhrPool = [];
$.xhrPool.abortAll = function() {
    $(this).each(function(i, jqXHR) { 
        jqXHR.abort();  
        $.xhrPool.splice(i, 1); 
    });
}
$.ajaxSetup({
    beforeSend: function(jqXHR) { $.xhrPool.push(jqXHR); },
    complete: function(jqXHR) {
        var i = $.xhrPool.indexOf(jqXHR);
        if (i > -1) $.xhrPool.splice(i, 1); 
    }
});

删除所有事件监听器,包括内联监听器

$("*").prop("onclick", null).off();

这将删除脚本并重新创建没有事件的元素

$('script').remove();
$('*').each(function(){
    $(this).replaceWith($(this).clone());   
});

如果网页上没有jQuery,则复制粘贴源代码到控制台。

可能还有其他的东西。请在评论中告诉我。

这是一个例子, 如果条件存在,则终止脚本。 我使用这个在我的SSE客户端javascript,如果

<script src="sse-clint.js" host="https://sse.host" query='["q1,"q2"]' ></script>

不能直接从JSON解析…

if( ! SSE_HOST  ) throw new Error(['[!] SSE.js: ERR_NOHOST - finished !']);

... 总之,总的思想是:

if( error==true) throw new Error([ 'You have This error' ,  'At this file', 'At this line'  ]);

这将终止/死亡你的javascript脚本

JavaScript相当于PHP的die。顺便说一句,它只是调用exit()(谢谢splattne):

function exit( status ) {
    // http://kevin.vanzonneveld.net
    // +   original by: Brett Zamir (http://brettz9.blogspot.com)
    // +      input by: Paul
    // +   bugfixed by: Hyam Singer (http://www.impact-computing.com/)
    // +   improved by: Philip Peterson
    // +   bugfixed by: Brett Zamir (http://brettz9.blogspot.com)
    // %        note 1: Should be considered expirimental. Please comment on this function.
    // *     example 1: exit();
    // *     returns 1: null

    var i;

    if (typeof status === 'string') {
        alert(status);
    }

    window.addEventListener('error', function (e) {e.preventDefault();e.stopPropagation();}, false);

    var handlers = [
        'copy', 'cut', 'paste',
        'beforeunload', 'blur', 'change', 'click', 'contextmenu', 'dblclick', 'focus', 'keydown', 'keypress', 'keyup', 'mousedown', 'mousemove', 'mouseout', 'mouseover', 'mouseup', 'resize', 'scroll',
        'DOMNodeInserted', 'DOMNodeRemoved', 'DOMNodeRemovedFromDocument', 'DOMNodeInsertedIntoDocument', 'DOMAttrModified', 'DOMCharacterDataModified', 'DOMElementNameChanged', 'DOMAttributeNameChanged', 'DOMActivate', 'DOMFocusIn', 'DOMFocusOut', 'online', 'offline', 'textInput',
        'abort', 'close', 'dragdrop', 'load', 'paint', 'reset', 'select', 'submit', 'unload'
    ];

    function stopPropagation (e) {
        e.stopPropagation();
        // e.preventDefault(); // Stop for the form controls, etc., too?
    }
    for (i=0; i < handlers.length; i++) {
        window.addEventListener(handlers[i], function (e) {stopPropagation(e);}, true);
    }

    if (window.stop) {
        window.stop();
    }

    throw '';
}

If you're looking for a way to forcibly terminate execution of all Javascript on a page, I'm not sure there is an officially sanctioned way to do that - it seems like the kind of thing that might be a security risk (although to be honest, I can't think of how it would be off the top of my head). Normally in Javascript when you want your code to stop running, you just return from whatever function is executing. (The return statement is optional if it's the last thing in the function and the function shouldn't return a value) If there's some reason returning isn't good enough for you, you should probably edit more detail into the question as to why you think you need it and perhaps someone can offer an alternate solution.

注意,在实践中,大多数浏览器的Javascript解释器在遇到错误时会简单地停止运行当前脚本。所以你可以做一些事情,比如访问一个未设置变量的属性:

function exit() {
    p.blah();
}

它可能会中止脚本。但你不应该指望它,因为它根本不是标准的,而且它看起来真的是一个糟糕的做法。

编辑:好吧,也许这不是一个很好的答案Ólafur的光。尽管他链接到的die()函数基本上实现了我的第二段,即它只是抛出一个错误。