SELECT COLUMN_NAME, IS_NULLABLE, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH FROM information_schema.columns WHERE table_name = '<name_of_table_or_view>'

在上面的语句中运行SELECT *，以查看information_schema. schema是什么。列的回报。

这个问题之前已经回答过了- https://stackoverflow.com/a/11268456/6169225

select
      c.name as [column name], 
      t.name as [type name],
      tbl.name as [table name]
from sys.columns c
         inner join sys.types t 
      on c.system_type_id = t.system_type_id 
         inner join sys.tables tbl
      on c.object_id = tbl.object_id
where
      c.object_id = OBJECT_ID('YourTableName1') 
          and 
      t.name like '%YourSearchDataType%'
union
(select
      c.name as [column name], 
      t.name as [type name],
      tbl.name as [table name]
from sys.columns c
         inner join sys.types t 
      on c.system_type_id = t.system_type_id 
         inner join sys.tables tbl
      on c.object_id = tbl.object_id
where
      c.object_id = OBJECT_ID('YourTableName2') 
          and 
      t.name like '%YourSearchDataType%')
union
(select
      c.name as [column name], 
      t.name as [type name],
      tbl.name as [table name]
from sys.columns c
         inner join sys.types t 
      on c.system_type_id = t.system_type_id 
         inner join sys.tables tbl
      on c.object_id = tbl.object_id
where
      c.object_id = OBJECT_ID('YourTableName3') 
          and 
      t.name like '%YourSearchDataType%')
order by tbl.name

根据一个数据库中三个不同表的搜索数据类型，搜索哪个列在哪个表中。这个查询可以扩展到'n'个表。

SELECT COLUMN_NAME, IS_NULLABLE, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH FROM information_schema.columns WHERE table_name = '<name_of_table_or_view>'

在上面的语句中运行SELECT *，以查看information_schema. schema是什么。列的回报。

这个问题之前已经回答过了- https://stackoverflow.com/a/11268456/6169225

SELECT  
   T.NAME AS [TABLE NAME]
   ,C.NAME AS [COLUMN NAME]
   ,P.NAME AS [DATA TYPE]
   ,P.MAX_LENGTH AS [Max_SIZE]
   ,C.[max_length] AS [ActualSizeUsed]
   ,CAST(P.PRECISION AS VARCHAR) +'/'+ CAST(P.SCALE AS VARCHAR) AS [PRECISION/SCALE]
FROM SYS.OBJECTS AS T
JOIN SYS.COLUMNS AS C
    ON T.OBJECT_ID = C.OBJECT_ID
JOIN SYS.TYPES AS P
    ON C.SYSTEM_TYPE_ID = P.SYSTEM_TYPE_ID
    AND C.[user_type_id] = P.[user_type_id]
WHERE T.TYPE_DESC='USER_TABLE'
  AND T.name = 'InventoryStatus'
ORDER BY 2

在SQL 2012中，你可以使用:

EXEC sp_describe_first_result_set N'SELECT * FROM [TableName]'

这将为您提供列名及其属性。

查询:执行sp_description _first_result_set并选择年收入 [DB_NAME]。[DBO]。(员工)”

注意:在某些ide中选择n之前是工作的，或者在某些ide中没有选择n是工作的