SELECT (WHEN first > second THEN second ELSE first END) the_minimal FROM table

对于SQL Server 2022+(或MySQL或PostgreSQL 9.3+)，更好的方法是使用LEAST和GREATEST函数。

SELECT GREATEST(A.date0, B.date0) AS date0, 
       LEAST(A.date1, B.date1, B.date2) AS date1
FROM A, B
WHERE B.x = A.x

:

GREATEST(value[，…]):返回所提供值中的最大(最大值)参数 LEAST(value[，…])从所提供的值中返回最小的(最小值)参数

文档链接:

MySQL http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html Postgres https://www.postgresql.org/docs/current/functions-conditional.html SQL Server https://learn.microsoft.com/en-us/sql/t-sql/functions/logical-functions-least-transact-sql

Select MIN(T.V) FROM (Select 1 as V UNION Select 2 as V) T

这最多适用于5个日期并处理空值。只是不能让它作为内联函数工作。

CREATE FUNCTION dbo.MinDate(@Date1 datetime = Null,
                            @Date2 datetime = Null,
                            @Date3 datetime = Null,
                            @Date4 datetime = Null,
                            @Date5 datetime = Null)
RETURNS Datetime AS
BEGIN
--USAGE select dbo.MinDate('20120405',null,null,'20110305',null)
DECLARE @Output datetime;

WITH Datelist_CTE(DT)
AS (
        SELECT @Date1 AS DT WHERE @Date1 is not NULL UNION
        SELECT @Date2 AS DT WHERE @Date2 is not NULL UNION
        SELECT @Date3 AS DT WHERE @Date3 is not NULL UNION
        SELECT @Date4 AS DT WHERE @Date4 is not NULL UNION
        SELECT @Date5 AS DT WHERE @Date5 is not NULL
   )
Select @Output=Min(DT) FROM Datelist_CTE;

RETURN @Output;
END;

使用CASE语句。

本页中的例子B应该接近你要做的事情: http://msdn.microsoft.com/en-us/library/ms181765.aspx

下面是该页面的代码:

使用AdventureWorks; 去 SELECT产品编号，名称，'价格范围' = 情况下 当ListPrice = 0 THEN '制造项目-不转售' 当ListPrice < 50 THEN 'Under $50' 当ListPrice >= 50 and ListPrice < 250 THEN '低于250美元' 当ListPrice >= 250 and ListPrice < 1000 THEN 'Under $1000' ELSE“超过1000美元” 结束 从生产。产品 按产品编号订购; 去

SELECT (WHEN first > second THEN second ELSE first END) the_minimal FROM table