我试图创建一个报告页面,显示从特定日期到特定日期的报告。这是我当前的代码:

$now = date('Y-m-d');
$reservations = Reservation::where('reservation_from', $now)->get();

这在普通SQL中所做的是从表中选择*,其中reservation_from = $now。

我在这里有这个问题,但我不知道如何将其转换为雄辩的问题。

SELECT * FROM table WHERE reservation_from BETWEEN '$from' AND '$to

如何将上面的代码转换为雄辩的查询?


当前回答

让我用准确的时间戳添加正确的语法

之前

$from = $request->from;
$to = $request->to;
Reservation::whereBetween('reservation_from', [$from, $to])->get();

$from = date('Y-m-d', strtotime($request->from));
$to = date('Y-m-d', strtotime($request->to));
Reservation::whereBetween('reservation_from', [$from, $to])->get();

注意:如果您以字符串形式存储日期,那么请确保在from和to中传递准确的格式。它将与DB匹配。

其他回答

如果你的字段是datetime而不是date(尽管它适用于这两种情况):

$fromDate = "2016-10-01";
$toDate = "2016-10-31";

$reservations = Reservation::whereRaw(
  "(reservation_from >= ? AND reservation_from <= ?)", 
  [
     $fromDate ." 00:00:00", 
     $toDate ." 23:59:59"
  ]
)->get();

我遵循了其他贡献者提供的有价值的解决方案,遇到了一个没有人解决的小问题。如果reservation_from是一个datetime列,那么它可能不会产生预期的结果,并且会错过所有日期相同但时间高于00:00:00时间的记录。为了改进上面的代码,一个小的调整是需要像这样。

$from = Carbon::parse();
$to = Carbon::parse();
$from = Carbon::parse('2018-01-01')->toDateTimeString();
//Include all the results that fall in $to date as well
$to = Carbon::parse('2018-05-02')
    ->addHours(23)
    ->addMinutes(59)
    ->addSeconds(59)
    ->toDateTimeString();
//Or $to can also be like so
$to = Carbon::parse('2018-05-02')
    ->addHours(24)
    ->toDateTimeString();
Reservation::whereBetween('reservation_from', [$from, $to])->get();

以下方法应该有效:

$now = date('Y-m-d');
$reservations = Reservation::where('reservation_from', '>=', $now)
                           ->where('reservation_from', '<=', $to)
                           ->get();

让我用准确的时间戳添加正确的语法

之前

$from = $request->from;
$to = $request->to;
Reservation::whereBetween('reservation_from', [$from, $to])->get();

$from = date('Y-m-d', strtotime($request->from));
$to = date('Y-m-d', strtotime($request->to));
Reservation::whereBetween('reservation_from', [$from, $to])->get();

注意:如果您以字符串形式存储日期,那么请确保在from和to中传递准确的格式。它将与DB匹配。

你可以使用DB::raw(")使列作为日期MySQL使用whereBetween函数如下:

    Reservation::whereBetween(DB::raw('DATE(`reservation_from`)'),
    [$request->from,$request->to])->get();