我试图创建一个报告页面，显示从特定日期到特定日期的报告。这是我当前的代码:
$now = date('Y-m-d');
$reservations = Reservation::where('reservation_from', $now)->get();
这在普通SQL中所做的是从表中选择*，其中reservation_from = $now。
我在这里有这个问题，但我不知道如何将其转换为雄辩的问题。
SELECT * FROM table WHERE reservation_from BETWEEN '$from' AND '$to
如何将上面的代码转换为雄辩的查询?
当前回答
让我用准确的时间戳添加正确的语法
之前
$from = $request->from;
$to = $request->to;
Reservation::whereBetween('reservation_from', [$from, $to])->get();
后
$from = date('Y-m-d', strtotime($request->from));
$to = date('Y-m-d', strtotime($request->to));
Reservation::whereBetween('reservation_from', [$from, $to])->get();
注意:如果您以字符串形式存储日期，那么请确保在from和to中传递准确的格式。它将与DB匹配。
其他回答
@masoud，在Laravel，你必须从表单请求字段值。所以,
Reservation::whereBetween('reservation_from',[$request->from,$request->to])->get();
而在livewire中，略有变化
Reservation::whereBetween('reservation_from',[$this->from,$this->to])->get();
以下方法应该有效:
$now = date('Y-m-d');
$reservations = Reservation::where('reservation_from', '>=', $now)
->where('reservation_from', '<=', $to)
->get();
你可以使用DB::raw(")使列作为日期MySQL使用whereBetween函数如下:
Reservation::whereBetween(DB::raw('DATE(`reservation_from`)'),
[$request->from,$request->to])->get();
如果你的字段是datetime而不是date(尽管它适用于这两种情况):
$fromDate = "2016-10-01";
$toDate = "2016-10-31";
$reservations = Reservation::whereRaw(
"(reservation_from >= ? AND reservation_from <= ?)",
[
$fromDate ." 00:00:00",
$toDate ." 23:59:59"
]
)->get();
如果你想检查当前日期是否存在于db中的两个日期之间: =>在这里，如果员工的申请从和到日期在今天存在，则查询将获得申请列表。
$list= (new LeaveApplication())
->whereDate('from','<=', $today)
->whereDate('to','>=', $today)
->get();
