我试图创建一个报告页面，显示从特定日期到特定日期的报告。这是我当前的代码:
$now = date('Y-m-d');
$reservations = Reservation::where('reservation_from', $now)->get();
这在普通SQL中所做的是从表中选择*，其中reservation_from = $now。
我在这里有这个问题，但我不知道如何将其转换为雄辩的问题。
SELECT * FROM table WHERE reservation_from BETWEEN '$from' AND '$to
如何将上面的代码转换为雄辩的查询?
当前回答
另一种方法:
use Illuminate\Support\Facades\DB;
$trans_from = date('2022-10-08');
$trans_to = date('2022-10-12');
$filter_transactions = DB::table('table_name_here')->whereBetween('created_at', [$trans_from, $trans_to])->get();
其他回答
诀窍在于改变它:
Reservation::whereBetween('reservation_from', [$from, $to])->get();
to
Reservation::whereBetween('reservation_from', ["$from", "$to"])->get();
因为mysql中的日期必须是字符串类型
你可以使用DB::raw(")使列作为日期MySQL使用whereBetween函数如下:
Reservation::whereBetween(DB::raw('DATE(`reservation_from`)'),
[$request->from,$request->to])->get();
如果你的字段是datetime而不是date(尽管它适用于这两种情况):
$fromDate = "2016-10-01";
$toDate = "2016-10-31";
$reservations = Reservation::whereRaw(
"(reservation_from >= ? AND reservation_from <= ?)",
[
$fromDate ." 00:00:00",
$toDate ." 23:59:59"
]
)->get();
试试这个:
因为你是基于单列值进行抓取，你可以同样简化你的查询:
$reservations = Reservation::whereBetween('reservation_from', array($from, $to))->get();
根据条件检索:laravel文档
希望这对你有所帮助。
@masoud，在Laravel，你必须从表单请求字段值。所以,
Reservation::whereBetween('reservation_from',[$request->from,$request->to])->get();
而在livewire中，略有变化
Reservation::whereBetween('reservation_from',[$this->from,$this->to])->get();
