你需要

set identity_insert YourTable ON

然后删除行并重新插入不同的标识。

插入完成后，不要忘记关闭identity_insert

set identity_insert YourTable OFF

您还可以使用SET IDENTITY INSERT来允许您将值插入到标识列中。

例子:

SET IDENTITY_INSERT dbo.Tool ON
GO

然后你可以在单位列中插入你需要的值。

c#程序员使用命令构建器的完整解决方案

首先，你要知道这些事实:

在任何情况下，都不能修改标识列，因此必须删除该行并重新添加新的标识。 不能从列中删除标识属性(必须删除到列) .net中的自定义命令构建器总是跳过标识列，因此不能将其用于此目的。

一旦知道了这个，你要做的就是。要么编写自己的SQL Insert语句，要么编写自己的Insert命令构建器。或者用我为你设计的这个。给定一个数据表，生成SQL插入脚本:

public static string BuildInsertSQLText ( DataTable table )
{
    StringBuilder sql = new StringBuilder(1000,5000000);
    StringBuilder values = new StringBuilder ( "VALUES (" );
    bool bFirst = true;
    bool bIdentity = false;
    string identityType = null;

    foreach(DataRow myRow in table.Rows) 
    {
        sql.Append( "\r\nINSERT INTO " + table.TableName + " (" );

        foreach ( DataColumn column in table.Columns )
        {
            if ( column.AutoIncrement )
            {
                bIdentity = true;

                switch ( column.DataType.Name )
                {
                    case "Int16":
                        identityType = "smallint";
                        break;
                    case "SByte":
                        identityType = "tinyint";
                        break;
                    case "Int64":
                        identityType = "bigint";
                        break;
                    case "Decimal":
                        identityType = "decimal";
                        break;
                    default:
                        identityType = "int";
                        break;
                }
            }
            else
            {
                if ( bFirst )
                    bFirst = false;
                else
                {
                    sql.Append ( ", " );
                    values.Append ( ", " );
                }
                sql.Append ("[");
                sql.Append ( column.ColumnName );
                sql.Append ("]");

                //values.Append (myRow[column.ColumnName].ToString() );

                if (myRow[column.ColumnName].ToString() == "True")
                    values.Append("1");
                else if (myRow[column.ColumnName].ToString() == "False")
                    values.Append("0");
                else if(myRow[column.ColumnName] == System.DBNull.Value)    
                    values.Append ("NULL");
                else if(column.DataType.ToString().Equals("System.String"))
                {
                    values.Append("'"+myRow[column.ColumnName].ToString()+"'");
                }
                else
                    values.Append (myRow[column.ColumnName].ToString());
                    //values.Append (column.DataType.ToString() );
            }
        }
        sql.Append ( ") " );
        sql.Append ( values.ToString () );
        sql.Append ( ")" );

        if ( bIdentity )
        {
            sql.Append ( "; SELECT CAST(scope_identity() AS " );
            sql.Append ( identityType );
            sql.Append ( ")" );
        }
        bFirst = true;
        sql.Append(";");
        values = new StringBuilder ( "VALUES (" );
    } //fin foreach
    return sql.ToString ();
}

这发生在我身上，因为我做了一个合并，它更新了我正在进行合并的ID。

失败的例子(注意ClownID):

    MERGE ArchitectMain.dbo.BackendClowns AS TGT 
   USING (
    SELECT ClownID
        ,ClownName
        ,Description
        ,Active
        ,EmailSubject
        ,AddedBy
        ,Added
    FROM #temptable1
    ) AS SRC(ClownID, ClownName, Description, Active, EmailSubject, AddedBy, Added)
    ON (TGT.ClownID = SRC.ClownID)
WHEN MATCHED
    THEN
        UPDATE
        SET ClownID = SRC.ClownID
            ,ClownName = SRC.ClownName
            ,Description = SRC.Description
            ,Active = SRC.Active
            ,EmailSubject = SRC.EmailSubject
            ,AddedBy = SRC.AddedBy
            ,Added = SRC.Added;

示例(注意ClownID):

MERGE ArchitectMain.dbo.BackendClowns AS TGT
USING (
    SELECT ClownID
        ,ClownName
        ,Description
        ,Active
        ,EmailSubject
        ,AddedBy
        ,Added
    FROM #temptable1
    ) AS SRC(ClownID, ClownName, Description, Active, EmailSubject, AddedBy, Added)
    ON (TGT.ClownID = SRC.ClownID)
WHEN MATCHED
    THEN
        UPDATE
        SET ClownName = SRC.ClownName
            ,Description = SRC.Description
            ,Active = SRC.Active
            ,EmailSubject = SRC.EmailSubject
            ,AddedBy = SRC.AddedBy
            ,Added = SRC.Added;
            

你需要

set identity_insert YourTable ON

然后删除行并重新插入不同的标识。

插入完成后，不要忘记关闭identity_insert

set identity_insert YourTable OFF

将您的表复制到没有标识列的新表。

    select columns into newtable from yourtable

用new seed添加一个标识列到newtable，并将其作为主键

    ALTER TABLE tableName ADD id MEDIUMINT NOT NULL AUTO_INCREMENT KEY