我想使用cURL不仅在HTTP POST中发送数据参数，而且还上传具有特定表单名称的文件。我该怎么做呢?
HTTP Post参数:
Userid = 12345 filecomment =这是一个映像文件
文件上传: 文件位置= /home/user1/Desktop/test.jpg file = image的表单名称(对应PHP端$_FILES['image'])
我认为cURL命令的一部分如下所示:
curl -d "userid=1&filecomment=This is an image file" --data-binary @"/home/user1/Desktop/test.jpg" localhost/uploader.php
我遇到的问题如下:
Notice: Undefined index: image in /var/www/uploader.php
问题是我使用$_FILES['image']在PHP脚本中拾取文件。
如何相应地调整cURL命令?
当前回答
cat test.txt
文件test.txt内容。
curl -v -F "hello=word" -F "file=@test.txt" https://httpbin.org/post
> POST /post HTTP/2
> Host: httpbin.org
> user-agent: curl/7.68.0
> accept: */*
> content-length: 307
> content-type: multipart/form-data; boundary=------------------------78a9f655d8c87a53
>
* Connection state changed (MAX_CONCURRENT_STREAMS == 128)!
* We are completely uploaded and fine
< HTTP/2 200
< date: Mon, 15 Nov 2021 06:18:47 GMT
< content-type: application/json
< content-length: 510
< server: gunicorn/19.9.0
< access-control-allow-origin: *
< access-control-allow-credentials: true
<
{
"args": {},
"data": "",
"files": {
"file": "file test.txt content.\n"
},
"form": {
"hello": "word"
},
"headers": {
"Accept": "*/*",
"Content-Length": "307",
"Content-Type": "multipart/form-data; boundary=------------------------78a9f655d8c87a53",
"Host": "httpbin.org",
"User-Agent": "curl/7.68.0",
"X-Amzn-Trace-Id": "Root=1-6191fbc7-6c68fead194d943d07148860"
},
"json": null,
"origin": "43.129.xx.xxx",
"url": "https://httpbin.org/post"
}
其他回答
下面是如何正确转义任意文件名的上传文件与bash:
#!/bin/bash
set -eu
f="$1"
f=${f//\\/\\\\}
f=${f//\"/\\\"}
f=${f//;/\\;}
curl --silent --form "uploaded=@\"$f\"" "$2"
我用这个命令curl -F 'filename=@/home/ yourhomedirectory /file.txt' http://yourserver/upload
cat test.txt
文件test.txt内容。
curl -v -F "hello=word" -F "file=@test.txt" https://httpbin.org/post
> POST /post HTTP/2
> Host: httpbin.org
> user-agent: curl/7.68.0
> accept: */*
> content-length: 307
> content-type: multipart/form-data; boundary=------------------------78a9f655d8c87a53
>
* Connection state changed (MAX_CONCURRENT_STREAMS == 128)!
* We are completely uploaded and fine
< HTTP/2 200
< date: Mon, 15 Nov 2021 06:18:47 GMT
< content-type: application/json
< content-length: 510
< server: gunicorn/19.9.0
< access-control-allow-origin: *
< access-control-allow-credentials: true
<
{
"args": {},
"data": "",
"files": {
"file": "file test.txt content.\n"
},
"form": {
"hello": "word"
},
"headers": {
"Accept": "*/*",
"Content-Length": "307",
"Content-Type": "multipart/form-data; boundary=------------------------78a9f655d8c87a53",
"Host": "httpbin.org",
"User-Agent": "curl/7.68.0",
"X-Amzn-Trace-Id": "Root=1-6191fbc7-6c68fead194d943d07148860"
},
"json": null,
"origin": "43.129.xx.xxx",
"url": "https://httpbin.org/post"
}
导致我到这里的问题原来是一个基本的用户错误——我没有在文件的路径中包含@符号，所以curl发布的是文件的路径/名称，而不是内容。Content-Length值因此是8，而不是我期望看到的给定测试文件长度的479。
当curl读取并发布文件时，将自动计算Content-Length头。
curl -i -H "Content-Type: application/xml"——data "@test.xml" -v -X POST https://<url>/<uri/
.．. < Content-Length: 479 .．.
把这贴在这里，以帮助其他的新手在未来。
你需要使用-F选项: -F/——form <name=content>指定HTTP多部分POST数据
试试这个:
curl \
-F "userid=1" \
-F "filecomment=This is an image file" \
-F "image=@/home/user1/Desktop/test.jpg" \
localhost/uploader.php
