我想使用cURL不仅在HTTP POST中发送数据参数,而且还上传具有特定表单名称的文件。我该怎么做呢?

HTTP Post参数:

Userid = 12345 filecomment =这是一个映像文件

文件上传: 文件位置= /home/user1/Desktop/test.jpg file = image的表单名称(对应PHP端$_FILES['image'])

我认为cURL命令的一部分如下所示:

curl -d "userid=1&filecomment=This is an image file" --data-binary @"/home/user1/Desktop/test.jpg" localhost/uploader.php

我遇到的问题如下:

Notice: Undefined index: image in /var/www/uploader.php

问题是我使用$_FILES['image']在PHP脚本中拾取文件。

如何相应地调整cURL命令?


当前回答

作为curl的替代方案,您可以使用HTTPie,它是一个CLI,类似于curl的人类工具。

安装说明:https://github.com/jakubroztocil/httpie#installation 然后,运行: http -f POST http://localhost:4040/api/users username=johnsnow photo@images/avatar.jpg Http /1.1 200 ok Access-Control-Expose-Headers: X-Frontend cache - control:不是商店 连接:维生 内容编码:gzip 内容长度:89 内容类型:text / html;charset = windows - 1251 时间:2018年6月26日星期二11:11:55 GMT 编译指示:no - cache Apache服务器: 不同:接受编码 X-Frontend: front623311 ...

其他回答

保存所有已发送文件到文件夹: 主机上的PHP文件。u.php:

<?php
$uploaddir = 'C:/VALID_DIR/';
 echo '<pre>';
foreach ($_FILES as $key => $file) {
    if(!isset($file) || !isset($file['name'])) continue;
    $uploadfile = $uploaddir . basename($file['name']);
   
    if (move_uploaded_file($file['tmp_name'], $uploadfile)) {
        echo "$key file > $uploadfile .\n";
    } else {
        echo " Error $key  file.\n";
    }
}
print_r($_FILES);
print "</pre>";?>

客户端使用:

curl -v -F filename=ff.xml -F upload=@ff.xml https://myhost.com/u.php

这对我来说很管用。

我的虚拟机崩溃了,它只有互联网连接。 我用这种方法恢复了一些文件。

经过多次尝试,这个命令对我来说是有效的:

curl -v -F filename=image.jpg -F upload=@image.jpg http://localhost:8080/api/upload

你需要使用-F选项: -F/——form <name=content>指定HTTP多部分POST数据

试试这个:

curl \
  -F "userid=1" \
  -F "filecomment=This is an image file" \
  -F "image=@/home/user1/Desktop/test.jpg" \
  localhost/uploader.php

这是我的解决方案,我读了很多帖子,它们真的很有帮助。最后我用cURL和PHP写了一些小文件的代码,我认为这真的很有用。

public function postFile()
{    
        $file_url = "test.txt";  //here is the file route, in this case is on same directory but you can set URL too like "http://examplewebsite.com/test.txt"
        $eol = "\r\n"; //default line-break for mime type
        $BOUNDARY = md5(time()); //random boundaryid, is a separator for each param on my post curl function
        $BODY=""; //init my curl body
        $BODY.= '--'.$BOUNDARY. $eol; //start param header
        $BODY .= 'Content-Disposition: form-data; name="sometext"' . $eol . $eol; // last Content with 2 $eol, in this case is only 1 content.
        $BODY .= "Some Data" . $eol;//param data in this case is a simple post data and 1 $eol for the end of the data
        $BODY.= '--'.$BOUNDARY. $eol; // start 2nd param,
        $BODY.= 'Content-Disposition: form-data; name="somefile"; filename="test.txt"'. $eol ; //first Content data for post file, remember you only put 1 when you are going to add more Contents, and 2 on the last, to close the Content Instance
        $BODY.= 'Content-Type: application/octet-stream' . $eol; //Same before row
        $BODY.= 'Content-Transfer-Encoding: base64' . $eol . $eol; // we put the last Content and 2 $eol,
        $BODY.= chunk_split(base64_encode(file_get_contents($file_url))) . $eol; // we write the Base64 File Content and the $eol to finish the data,
        $BODY.= '--'.$BOUNDARY .'--' . $eol. $eol; // we close the param and the post width "--" and 2 $eol at the end of our boundary header.



        $ch = curl_init(); //init curl
        curl_setopt($ch, CURLOPT_HTTPHEADER, array(
                         'X_PARAM_TOKEN : 71e2cb8b-42b7-4bf0-b2e8-53fbd2f578f9' //custom header for my api validation you can get it from $_SERVER["HTTP_X_PARAM_TOKEN"] variable
                         ,"Content-Type: multipart/form-data; boundary=".$BOUNDARY) //setting our mime type for make it work on $_FILE variable
                    );
        curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/1.0 (Windows NT 6.1; WOW64; rv:28.0) Gecko/20100101 Firefox/28.0'); //setting our user agent
        curl_setopt($ch, CURLOPT_URL, "api.endpoint.post"); //setting our api post url
        curl_setopt($ch, CURLOPT_COOKIEJAR, $BOUNDARY.'.txt'); //saving cookies just in case we want
        curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); // call return content
        curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); navigate the endpoint
        curl_setopt($ch, CURLOPT_POST, true); //set as post
        curl_setopt($ch, CURLOPT_POSTFIELDS, $BODY); // set our $BODY 


        $response = curl_exec($ch); // start curl navigation

     print_r($response); //print response

}

这样我们就可以得到api。endpoint。张贴“以下vars张贴。您可以很容易地使用这个脚本进行测试,并且您应该在最后一行收到关于函数postFile()的调试。

print_r($response); //print response

public function getPostFile()
{

    echo "\n\n_SERVER\n";
    echo "<pre>";
    print_r($_SERVER['HTTP_X_PARAM_TOKEN']);
    echo "/<pre>";
    echo "_POST\n";
    echo "<pre>";
    print_r($_POST['sometext']);
    echo "/<pre>";
    echo "_FILES\n";
    echo "<pre>";
    print_r($_FILEST['somefile']);
    echo "/<pre>";
}

它应该工作得很好,它们可能是更好的解决方案,但这确实有助于理解边界和multipart/from-data mime如何在PHP和cURL库上工作。

下面是如何正确转义任意文件名的上传文件与bash:

#!/bin/bash
set -eu

f="$1"
f=${f//\\/\\\\}
f=${f//\"/\\\"}
f=${f//;/\\;}

curl --silent --form "uploaded=@\"$f\"" "$2"