是否有一种方法将枚举转换为包含所有枚举选项的列表?


当前回答

如果你想Enum int作为键和名称作为值,如果你存储的数字到数据库,它是从Enum!

void Main()
{
     ICollection<EnumValueDto> list = EnumValueDto.ConvertEnumToList<SearchDataType>();

     foreach (var element in list)
     {
        Console.WriteLine(string.Format("Key: {0}; Value: {1}", element.Key, element.Value));
     }

     /* OUTPUT:
        Key: 1; Value: Boolean
        Key: 2; Value: DateTime
        Key: 3; Value: Numeric         
     */
}

public class EnumValueDto
{
    public int Key { get; set; }

    public string Value { get; set; }

    public static ICollection<EnumValueDto> ConvertEnumToList<T>() where T : struct, IConvertible
    {
        if (!typeof(T).IsEnum)
        {
            throw new Exception("Type given T must be an Enum");
        }

        var result = Enum.GetValues(typeof(T))
                         .Cast<T>()
                         .Select(x =>  new EnumValueDto { Key = Convert.ToInt32(x), 
                                       Value = x.ToString(new CultureInfo("en")) })
                         .ToList()
                         .AsReadOnly();

        return result;
    }
}

public enum SearchDataType
{
    Boolean = 1,
    DateTime,
    Numeric
}

其他回答

你可以使用下面的泛型方法:

public static List<T> GetItemsList<T>(this int enums) where T : struct, IConvertible
{
    if (!typeof (T).IsEnum)
    {
        throw new Exception("Type given must be an Enum");
    }

    return (from int item in Enum.GetValues(typeof (T))
            where (enums & item) == item
            select (T) Enum.Parse(typeof (T), item.ToString(new CultureInfo("en")))).ToList();
}

非常简单的答案

下面是我在一个应用程序中使用的属性

public List<string> OperationModes
{
    get
    {
       return Enum.GetNames(typeof(SomeENUM)).ToList();
    }
}
private List<SimpleLogType> GetLogType()
{
  List<SimpleLogType> logList = new List<SimpleLogType>();
  SimpleLogType internalLogType;
  foreach (var logtype in Enum.GetValues(typeof(Log)))
  {
    internalLogType = new SimpleLogType();
    internalLogType.Id = (int) (Log) Enum.Parse(typeof (Log), logtype.ToString(), true);
    internalLogType.Name = (Log)Enum.Parse(typeof(Log), logtype.ToString(), true);
    logList.Add(internalLogType);
  }
  return logList;
}

在top Code中,Log是一个枚举,SimpleLogType是一个日志结构。

public enum Log
{
  None = 0,
  Info = 1,
  Warning = 8,
  Error = 3
}

下面是我喜欢的使用LINQ的方式:

public class EnumModel
{
    public int Value { get; set; }
    public string Name { get; set; }
}

public enum MyEnum
{
    Name1=1,
    Name2=2,
    Name3=3
}

public class Test
{
        List<EnumModel> enums = ((MyEnum[])Enum.GetValues(typeof(MyEnum))).Select(c => new EnumModel() { Value = (int)c, Name = c.ToString() }).ToList();

        // A list of Names only, does away with the need of EnumModel 
        List<string> MyNames = ((MyEnum[])Enum.GetValues(typeof(MyEnum))).Select(c => c.ToString()).ToList();

        // A list of Values only, does away with the need of EnumModel 
        List<int> myValues = ((MyEnum[])Enum.GetValues(typeof(MyEnum))).Select(c => (int)c).ToList();

        // A dictionnary of <string,int>
        Dictionary<string,int> myDic = ((MyEnum[])Enum.GetValues(typeof(MyEnum))).ToDictionary(k => k.ToString(), v => (int)v);
}

希望能有所帮助

public class NameValue
{
    public string Name { get; set; }
    public object Value { get; set; }
}

public class NameValue
{
    public string Name { get; set; }
    public object Value { get; set; }
}

public static List<NameValue> EnumToList<T>()
{
    var array = (T[])(Enum.GetValues(typeof(T)).Cast<T>()); 
    var array2 = Enum.GetNames(typeof(T)).ToArray<string>(); 
    List<NameValue> lst = null;
    for (int i = 0; i < array.Length; i++)
    {
        if (lst == null)
            lst = new List<NameValue>();
        string name = array2[i];
        T value = array[i];
        lst.Add(new NameValue { Name = name, Value = value });
    }
    return lst;
}

转换枚举到一个列表更多的信息可在这里。