如何从数组中删除一个特定值? 类似 :
array.remove(value);
我必须使用核心核心核心JavaScript。 不允许框架 。
当前回答
不可改变和一班制方式:
const newArr = targetArr.filter(e => e !== elementToDelete);
其他回答
Vanilla JavaScript(ES5.1) - (ES5.1) -已经到位版本版本
浏览器支持 :因特网探索者 9或以后(或以后(详细浏览器支持)
/**
* Removes all occurences of the item from the array.
*
* Modifies the array “in place”, i.e. the array passed as an argument
* is modified as opposed to creating a new array. Also returns the modified
* array for your convenience.
*/
function removeInPlace(array, item) {
var foundIndex, fromIndex;
// Look for the item (the item can have multiple indices)
fromIndex = array.length - 1;
foundIndex = array.lastIndexOf(item, fromIndex);
while (foundIndex !== -1) {
// Remove the item (in place)
array.splice(foundIndex, 1);
// Bookkeeping
fromIndex = foundIndex - 1;
foundIndex = array.lastIndexOf(item, fromIndex);
}
// Return the modified array
return array;
}
Vanilla JavaScript(ES5.1) - (ES5.1) -不可变版本版本
浏览器支持: 与原版的香草 JavaScript 相同
/**
* Removes all occurences of the item from the array.
*
* Returns a new array with all the items of the original array except
* the specified item.
*/
function remove(array, item) {
var arrayCopy;
arrayCopy = array.slice();
return removeInPlace(arrayCopy, item);
}
香草ES6 -不可变版本版本
浏览器支持: Chrome 46, 边缘 12, Firefox 16, Opera 37, Safari 8 ()详细浏览器支持)
/**
* Removes all occurences of the item from the array.
*
* Returns a new array with all the items of the original array except
* the specified item.
*/
function remove(array, item) {
// Copy the array
array = [...array];
// Look for the item (the item can have multiple indices)
let fromIndex = array.length - 1;
let foundIndex = array.lastIndexOf(item, fromIndex);
while (foundIndex !== -1) {
// Remove the item by generating a new array without it
array = [
...array.slice(0, foundIndex),
...array.slice(foundIndex + 1),
];
// Bookkeeping
fromIndex = foundIndex - 1;
foundIndex = array.lastIndexOf(item, fromIndex)
}
// Return the new array
return array;
}
Array.prototype.removeByValue = function (val) {
for (var i = 0; i < this.length; i++) {
if (this[i] === val) {
this.splice(i, 1);
i--;
}
}
return this;
}
var fruits = ['apple', 'banana', 'carrot', 'orange'];
fruits.removeByValue('banana');
console.log(fruits);
// -> ['apple', 'carrot', 'orange']如果您想要删除删除位置的新数组,您可以总是删除特定元素,并过滤该数组。它可能需要扩展矩阵对象对于不执行过滤法的浏览器来说,但从长远来看,它更容易,因为你所做的只是这个:
var my_array = [1, 2, 3, 4, 5, 6];
delete my_array[4];
console.log(my_array.filter(function(a){return typeof a !== 'undefined';}));
它应显示[1, 2, 3, 4, 6].
使用数组过滤过滤器方法 :
let array = [1, 2, 3, 4, 511, 34, 511, 78, 88];
let value = 511;
array = array.filter(element => element !== value);
console.log(array)
使用使用jj 查询. grep ():
var y = [1, 2, 3, 9, 4]
var removeItem = 9;
y = jQuery.grep(y, function(value) {
return value != removeItem;
});
console.log(y)<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>