如何从数组中删除一个特定值? 类似 :

array.remove(value);

我必须使用核心核心核心JavaScript。 不允许框架 。


当前回答

使用 JavaScript 原型特性定义列对象上名为删除() 的方法 。

使用使用复数()满足要求的方法。

请看看下面的代码

Array.prototype.remove = function(item) {
    // 'index' will have -1 if 'item' does not exist,
    // else it will have the index of the first item found in the array
    var index = this.indexOf(item);

    if (index > -1) {
        // The splice() method is used to add/remove items(s) in the array
        this.splice(index, 1);
    }
    return index;
}

var arr = [ 11, 22, 67, 45, 61, 89, 34, 12, 7, 8, 3, -1, -4];

// Printing array
// [ 11, 22, 67, 45, 61, 89, 34, 12, 7, 8, 3, -1, -4];
console.log(arr)

// Removing 67 (getting its index, i.e. 2)
console.log("Removing 67")
var index = arr.remove(67)

if (index > 0){
    console.log("Item 67 found at ", index)
} else {
    console.log("Item 67 does not exist in array")
}

// Printing updated array
// [ 11, 22, 45, 61, 89, 34, 12, 7, 8, 3, -1, -4];
console.log(arr)

// ............... Output ................................
// [ 11, 22, 67, 45, 61, 89, 34, 12, 7, 8, 3, -1, -4 ]
// Removing 67
// Item 67 found at  2
// [ 11, 22, 45, 61, 89, 34, 12, 7, 8, 3, -1, -4 ]

注:下面是用完整示例代码执行的完整示例代码。REPL编号js REPL来描述推 ()、 流行 ()、 转移 ()、 非转移 () 和 组合 () 方法的使用 。

> // Defining an array
undefined
> var arr = [12, 45, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34];
undefined
> // Getting length of array
undefined
> arr.length;
16
> // Adding 1 more item at the end i.e. pushing an item
undefined
> arr.push(55);
17
> arr
[ 12, 45, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34, 55 ]
> // Popping item from array (i.e. from end)
undefined
> arr.pop()
55
> arr
[ 12, 45, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
> // Remove item from beginning
undefined
> arr.shift()
12
> arr
[ 45, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
> // Add item(s) at beginning
undefined
> arr.unshift(67); // Add 67 at beginning of the array and return number of items in updated/new array
16
> arr
[ 67, 45, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
> arr.unshift(11, 22); // Adding 2 more items at the beginning of array
18
> arr
[ 11, 22, 67, 45, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
>
> // Define a method on array (temporarily) to remove an item and return the index of removed item; if it is found else return -1
undefined
> Array.prototype.remove = function(item) {
... var index = this.indexOf(item);
... if (index > -1) {
..... this.splice(index, 1); // splice() method is used to add/remove items in array
..... }
... return index;
... }
[Function]
>
> arr
[ 11, 22, 67, 45, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
>
> arr.remove(45);    // Remove 45 (you will get the index of removed item)
3
> arr
[ 11, 22, 67, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
>
> arr.remove(22)    // Remove 22
1
> arr
[ 11, 67, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
> arr.remove(67)    // Remove 67
1
> arr
[ 11, 67, 89, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
>
> arr.remove(89)    // Remove 89
2
> arr
[ 11, 67, 34, 12, 7, 8, 3, -1, -4, -11, 0, 56, 12, 34 ]
>
> arr.remove(100);  // 100 doesn't exist, remove() will return -1
-1
>

其他回答

正在删除带有索引和相交点的值 !

function removeArrValue(arr,value) {
    var index = arr.indexOf(value);
    if (index > -1) {
        arr.splice(index, 1);
    }
    return arr;
}

我本人也有这个问题(在更换阵列是可以接受的情况下),

var filteredItems = this.items.filter(function (i) {
    return i !== item;
});

要给上面的片段略加上下文:

self.thingWithItems = {
    items: [],
    removeItem: function (item) {
        var filteredItems = this.items.filter(function (i) {
            return i !== item;
        });

        this.items = filteredItems;
    }
};

此解决方案应该同时使用引用项和值项。 它都取决于您是否需要保持对原始数组的引用, 以判断该解决方案是否适用 。

您可以使用lodash_.pull(平衡数组). pullAt(阵数数组)或_. 无 _(不变异阵列)

var array1 = ['a', 'b', 'c', 'd']
_.pull(array1, 'c')
console.log(array1) // ['a', 'b', 'd']

var array2 = ['e', 'f', 'g', 'h']
_.pullAt(array2, 0)
console.log(array2) // ['f', 'g', 'h']

var array3 = ['i', 'j', 'k', 'l']
var newArray = _.without(array3, 'i') // ['j', 'k', 'l']
console.log(array3) // ['i', 'j', 'k', 'l']

使用 jQuery 的阵列 :

A = [1, 2, 3, 4, 5, 6];
A.splice($.inArray(3, A), 1);
//It will return A=[1, 2, 4, 5, 6]`   

注意: 如果元素未找到, 在阵列中返回 - 1 。

Array.prototype.removeItem = function(a) {
    for (i = 0; i < this.length; i++) {
        if (this[i] == a) {
            for (i2 = i; i2 < this.length - 1; i2++) {
                this[i2] = this[i2 + 1];
            }
            this.length = this.length - 1
            return;
        }
    }
}

var recentMovies = ['Iron Man', 'Batman', 'Superman', 'Spiderman'];
recentMovies.removeItem('Superman');