使用fs-extra包，你可以用一行代码做到这一点:

const fs = require('fs-extra');

const dir = '/tmp/this/path/does/not/exist';
fs.ensureDirSync(dir);

使用fs-extra包，你可以用一行代码做到这一点:

const fs = require('fs-extra');

const dir = '/tmp/this/path/does/not/exist';
fs.ensureDirSync(dir);

单行版本:

// Or in TypeScript: import * as fs from 'fs';
const fs = require('fs');
!fs.existsSync(dir) && fs.mkdirSync(dir);

最好的解决方案是使用名为node-fs-extra的npm模块。它有一个名为mkdir的方法，用于创建您提到的目录。如果您给出一个较长的目录路径，它将自动创建父文件夹。这个模块是npm模块fs的超集，所以如果你添加了这个模块，你也可以使用fs中的所有函数。

如果子目录不存在，我必须创建子目录。我用了这个:

const path = require('path');
const fs = require('fs');

function ensureDirectoryExists(p) {
    //console.log(ensureDirectoryExists.name, {p});
    const d = path.dirname(p);
    if (d && d !== p) {
        ensureDirectoryExists(d);
    }
    if (!fs.existsSync(d)) {
        fs.mkdirSync(d);
    }
}

异步执行此操作的函数(从使用同步函数的SO上的类似答案调整，我现在找不到)

// ensure-directory.js
import { mkdir, access } from 'fs'

/**
 * directoryPath is a path to a directory (no trailing file!)
 */
export default async directoryPath => {
  directoryPath = directoryPath.replace(/\\/g, '/')

  // -- preparation to allow absolute paths as well
  let root = ''
  if (directoryPath[0] === '/') {
    root = '/'
    directoryPath = directoryPath.slice(1)
  } else if (directoryPath[1] === ':') {
    root = directoryPath.slice(0, 3) // c:\
    directoryPath = directoryPath.slice(3)
  }

  // -- create folders all the way down
  const folders = directoryPath.split('/')
  let folderPath = `${root}`
  for (const folder of folders) {
    folderPath = `${folderPath}${folder}/`

    const folderExists = await new Promise(resolve =>
      access(folderPath, error => {
        if (error) {
          resolve(false)
        }
        resolve(true)
      })
    )

    if (!folderExists) {
      await new Promise((resolve, reject) =>
        mkdir(folderPath, error => {
          if (error) {
            reject('Error creating folderPath')
          }
          resolve(folderPath)
        })
      )
    }
  }
}