def count_em(valid_path):
   x = 0
   for root, dirs, files in os.walk(valid_path):
       for f in files:
            x = x+1
print "There are", x, "files in this directory."
return x

摘自本文

def count_em(valid_path):
   x = 0
   for root, dirs, files in os.walk(valid_path):
       for f in files:
            x = x+1
print "There are", x, "files in this directory."
return x

摘自本文

它使用os。Listdir，适用于任何目录:

import os
directory = 'mydirpath'

number_of_files = len([item for item in os.listdir(directory) if os.path.isfile(os.path.join(directory, item))])

这可以用一个生成器来简化，用以下方法可以更快一点:

import os
isfile = os.path.isfile
join = os.path.join

directory = 'mydirpath'
number_of_files = sum(1 for item in os.listdir(directory) if isfile(join(directory, item)))

我想扩展@Mr_and_Mrs_D的回复:

import os
folder = 'C:/Dropbox'
file_count = sum(len(files) for _, _, files in os.walk(folder))
print(file_count)

这将计算文件夹及其子文件夹中的所有文件。然而，如果你想做一些过滤——比如只计算以.svg结尾的文件，你可以这样做:

import os
file_count = sum(len([f for f in files if f.endswith('.svg')]) for _, _, files in os.walk(folder))
print(file_count)

你基本上可以替换:

len(档案)

:

Len ([f for f in files if f.endswith('.svg')])

import os

_, _, files = next(os.walk("/usr/lib"))
file_count = len(files)

我这样做了，这返回了文件夹(Attack_Data)中的文件数量…这很好。

import os
def fcount(path):
    #Counts the number of files in a directory
    count = 0
    for f in os.listdir(path):
        if os.path.isfile(os.path.join(path, f)):
            count += 1

    return count
path = r"C:\Users\EE EKORO\Desktop\Attack_Data" #Read files in folder
print (fcount(path))