如何只计算目录中的文件?这将目录本身计算为一个文件:
len(glob.glob('*'))
如何只计算目录中的文件?这将目录本身计算为一个文件:
len(glob.glob('*'))
当前回答
对于所有类型的文件,包括子目录(Python 2):
import os
lst = os.listdir(directory) # your directory path
number_files = len(lst)
print number_files
只有文件(避免子目录):
import os
onlyfiles = next(os.walk(directory))[2] #directory is your directory path as string
print len(onlyfiles)
其他回答
import os
_, _, files = next(os.walk("/usr/lib"))
file_count = len(files)
import os
def count_files(in_directory):
joiner= (in_directory + os.path.sep).__add__
return sum(
os.path.isfile(filename)
for filename
in map(joiner, os.listdir(in_directory))
)
>>> count_files("/usr/lib")
1797
>>> len(os.listdir("/usr/lib"))
2049
一行和递归:
def count_files(path):
return sum([len(files) for _, _, files in os.walk(path)])
count_files('path/to/dir')
def count_em(valid_path):
x = 0
for root, dirs, files in os.walk(valid_path):
for f in files:
x = x+1
print "There are", x, "files in this directory."
return x
摘自本文
它使用os。Listdir,适用于任何目录:
import os
directory = 'mydirpath'
number_of_files = len([item for item in os.listdir(directory) if os.path.isfile(os.path.join(directory, item))])
这可以用一个生成器来简化,用以下方法可以更快一点:
import os
isfile = os.path.isfile
join = os.path.join
directory = 'mydirpath'
number_of_files = sum(1 for item in os.listdir(directory) if isfile(join(directory, item)))