好的，在这里我比较两个函数，一个由我自己(regExp)和另一个由(annakata)。

将数组:

function insertParam(key, value)
{
    key = escape(key); value = escape(value);

    var kvp = document.location.search.substr(1).split('&');

    var i=kvp.length; var x; while(i--) 
    {
        x = kvp[i].split('=');

        if (x[0]==key)
        {
                x[1] = value;
                kvp[i] = x.join('=');
                break;
        }
    }

    if(i<0) {kvp[kvp.length] = [key,value].join('=');}

    //this will reload the page, it's likely better to store this until finished
    return "&"+kvp.join('&'); 
}

正则表达式的方法:

function addParameter(param, value)
{
    var regexp = new RegExp("(\\?|\\&)" + param + "\\=([^\\&]*)(\\&|$)");
    if (regexp.test(document.location.search)) 
        return (document.location.search.toString().replace(regexp, function(a, b, c, d)
        {
                return (b + param + "=" + value + d);
        }));
    else 
        return document.location.search+ param + "=" + value;
}

测试用例:

time1=(new Date).getTime();
for (var i=0;i<10000;i++)
{
addParameter("test","test");
}
time2=(new Date).getTime();
for (var i=0;i<10000;i++)
{
insertParam("test","test");
}

time3=(new Date).getTime();

console.log((time2-time1)+" "+(time3-time2));

似乎即使使用最简单的解决方案(当regexp只使用test而不输入.replace函数时)，它仍然比分裂要慢…好。Regexp有点慢，但是…喔…

你可以使用URLSearchParams

const urlParams = new URLSearchParams(window.location.search);

urlParams.set('order', 'date');

window.location.search = urlParams;

.第一个农业是关键，第二个是价值。

注意:这在任何版本的ie浏览器中都不支持(但在Edge中支持)

就我所知，上面的答案都没有解决查询字符串包含参数的情况，这些参数本身就是一个数组，因此会出现不止一次，例如:

http://example.com?sizes[]=a&sizes[]=b

下面的函数是我用来更新document.location.search的。它接受一个键/值对数组作为参数，它将返回一个修改后的版本，你可以做任何你想做的事情。我是这样使用的:

var newParams = [
    ['test','123'],
    ['best','456'],
    ['sizes[]','XXL']
];
var newUrl = document.location.pathname + insertParams(newParams);
history.replaceState('', '', newUrl);

如果当前url为:

http://example.com/index.php?test=replaceme&sizes [] = XL

这会让你

http://example.com/index.php?test=123&sizes[]=XL&尺寸[]=XXL&best=456

函数

function insertParams(params) {
    var result;
    var ii = params.length;
    var queryString = document.location.search.substr(1);
    var kvps = queryString ? queryString.split('&') : [];
    var kvp;
    var skipParams = [];
    var i = kvps.length;
    while (i--) {
        kvp = kvps[i].split('=');
        if (kvp[0].slice(-2) != '[]') {
            var ii = params.length;
            while (ii--) {
                if (params[ii][0] == kvp[0]) {
                    kvp[1] = params[ii][1];
                    kvps[i] = kvp.join('=');
                    skipParams.push(ii);
                }
            }
        }
    }
    var ii = params.length;
    while (ii--) {
        if (skipParams.indexOf(ii) === -1) {
            kvps.push(params[ii].join('='));
        }
    }
    result = kvps.length ? '?' + kvps.join('&') : '';
    return result;
}

你需要适应的基本实现是这样的:

function insertParam(key, value) {
    key = encodeURIComponent(key);
    value = encodeURIComponent(value);

    // kvp looks like ['key1=value1', 'key2=value2', ...]
    var kvp = document.location.search.substr(1).split('&');
    let i=0;

    for(; i<kvp.length; i++){
        if (kvp[i].startsWith(key + '=')) {
            let pair = kvp[i].split('=');
            pair[1] = value;
            kvp[i] = pair.join('=');
            break;
        }
    }

    if(i >= kvp.length){
        kvp[kvp.length] = [key,value].join('=');
    }

    // can return this or...
    let params = kvp.join('&');

    // reload page with new params
    document.location.search = params;
}

这大约是正则表达式或基于搜索的解决方案的两倍，但这完全取决于查询字符串的长度和任何匹配的索引

为了完成起见，我以慢速regex方法为基准(大约慢了150%)

function insertParam2(key,value)
{
    key = encodeURIComponent(key); value = encodeURIComponent(value);

    var s = document.location.search;
    var kvp = key+"="+value;

    var r = new RegExp("(&|\\?)"+key+"=[^\&]*");

    s = s.replace(r,"$1"+kvp);

    if(!RegExp.$1) {s += (s.length>0 ? '&' : '?') + kvp;};

    //again, do what you will here
    document.location.search = s;
}

这是我自己的尝试，但我将使用annakata的答案，因为它看起来更清晰:

function AddUrlParameter(sourceUrl, parameterName, parameterValue, replaceDuplicates)
{
    if ((sourceUrl == null) || (sourceUrl.length == 0)) sourceUrl = document.location.href;
    var urlParts = sourceUrl.split("?");
    var newQueryString = "";
    if (urlParts.length > 1)
    {
        var parameters = urlParts[1].split("&");
        for (var i=0; (i < parameters.length); i++)
        {
            var parameterParts = parameters[i].split("=");
            if (!(replaceDuplicates && parameterParts[0] == parameterName))
            {
                if (newQueryString == "")
                    newQueryString = "?";
                else
                    newQueryString += "&";
                newQueryString += parameterParts[0] + "=" + parameterParts[1];
            }
        }
    }
    if (newQueryString == "")
        newQueryString = "?";
    else
        newQueryString += "&";
    newQueryString += parameterName + "=" + parameterValue;

    return urlParts[0] + newQueryString;
}

另外，我从stackoverflow上的另一篇文章中找到了这个jQuery插件，如果你需要更多的灵活性，你可以使用它: http://plugins.jquery.com/project/query-object

我认为代码应该是(还没有测试):

return $.query.parse(sourceUrl).set(parameterName, parameterValue).toString();

/** * Add a URL parameter * @param {string} url * @param {string} param the key to set * @param {string} value */ var addParam = function(url, param, value) { param = encodeURIComponent(param); var a = document.createElement('a'); param += (value ? "=" + encodeURIComponent(value) : ""); a.href = url; a.search += (a.search ? "&" : "") + param; return a.href; } /** * Add a URL parameter (or modify if already exists) * @param {string} url * @param {string} param the key to set * @param {string} value */ var addOrReplaceParam = function(url, param, value) { param = encodeURIComponent(param); var r = "([&?]|&)" + param + "\\b(?:=(?:[^&#]*))*"; var a = document.createElement('a'); var regex = new RegExp(r); var str = param + (value ? "=" + encodeURIComponent(value) : ""); a.href = url; var q = a.search.replace(regex, "$1"+str); if (q === a.search) { a.search += (a.search ? "&" : "") + str; } else { a.search = q; } return a.href; } url = "http://www.example.com#hashme"; newurl = addParam(url, "ciao", "1"); alert(newurl);

请注意，参数应该在被追加到查询字符串之前进行编码。

http://jsfiddle.net/48z7z4kx/