在一个使用AJAX调用的web应用程序中,我需要提交一个请求,但在URL的末尾添加一个参数,例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数,该函数解析URL并查看每个参数,然后添加新参数或更新已经存在的值。
在一个使用AJAX调用的web应用程序中,我需要提交一个请求,但在URL的末尾添加一个参数,例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数,该函数解析URL并查看每个参数,然后添加新参数或更新已经存在的值。
当前回答
加入@Vianney的回答https://stackoverflow.com/a/44160941/6609678
我们可以导入node中的内置URL模块,如下所示
const { URL } = require('url');
例子:
Terminal $ node
> const { URL } = require('url');
undefined
> let url = new URL('', 'http://localhost:1989/v3/orders');
undefined
> url.href
'http://localhost:1989/v3/orders'
> let fetchAll=true, timePeriod = 30, b2b=false;
undefined
> url.href
'http://localhost:1989/v3/orders'
> url.searchParams.append('fetchAll', fetchAll);
undefined
> url.searchParams.append('timePeriod', timePeriod);
undefined
> url.searchParams.append('b2b', b2b);
undefined
> url.href
'http://localhost:1989/v3/orders?fetchAll=true&timePeriod=30&b2b=false'
> url.toString()
'http://localhost:1989/v3/orders?fetchAll=true&timePeriod=30&b2b=false'
有用的链接:
https://developer.mozilla.org/en-US/docs/Web/API/URL https://developer.mozilla.org/en/docs/Web/API/URLSearchParams
其他回答
我有一个'类',这是:
function QS(){
this.qs = {};
var s = location.search.replace( /^\?|#.*$/g, '' );
if( s ) {
var qsParts = s.split('&');
var i, nv;
for (i = 0; i < qsParts.length; i++) {
nv = qsParts[i].split('=');
this.qs[nv[0]] = nv[1];
}
}
}
QS.prototype.add = function( name, value ) {
if( arguments.length == 1 && arguments[0].constructor == Object ) {
this.addMany( arguments[0] );
return;
}
this.qs[name] = value;
}
QS.prototype.addMany = function( newValues ) {
for( nv in newValues ) {
this.qs[nv] = newValues[nv];
}
}
QS.prototype.remove = function( name ) {
if( arguments.length == 1 && arguments[0].constructor == Array ) {
this.removeMany( arguments[0] );
return;
}
delete this.qs[name];
}
QS.prototype.removeMany = function( deleteNames ) {
var i;
for( i = 0; i < deleteNames.length; i++ ) {
delete this.qs[deleteNames[i]];
}
}
QS.prototype.getQueryString = function() {
var nv, q = [];
for( nv in this.qs ) {
q[q.length] = nv+'='+this.qs[nv];
}
return q.join( '&' );
}
QS.prototype.toString = QS.prototype.getQueryString;
//examples
//instantiation
var qs = new QS;
alert( qs );
//add a sinle name/value
qs.add( 'new', 'true' );
alert( qs );
//add multiple key/values
qs.add( { x: 'X', y: 'Y' } );
alert( qs );
//remove single key
qs.remove( 'new' )
alert( qs );
//remove multiple keys
qs.remove( ['x', 'bogus'] )
alert( qs );
我已经重写了toString方法,所以不需要调用QS::getQueryString,你可以使用QS::toString,或者像我在示例中所做的那样,仅仅依赖于对象被强制转换为字符串。
这是一个添加查询参数的简单方法:
const query = new URLSearchParams(window.location.search);
query.append("enabled", "true");
这就是这里更多的内容。
请注意支持规格。
如果你有一个url字符串,你想用一个参数来装饰,你可以试试这个在线程序:
urlstring += ( urlstring.match( /[\?]/g ) ? '&' : '?' ) + 'param=value';
这意味着什么?将是参数的前缀,但如果已经有?在urlstring中,than &将是前缀。
我也会建议做encodeURI(paramvariable),如果你没有硬编码参数,但它是在一个paramvariable;或者里面有有趣的角色。
encodeURI函数的使用请参见javascript URL编码。
以下功能将帮助您添加,更新和删除参数或从URL。
/ / example1and
var myURL = '/search';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?location=california
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?location=new%20york
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search
/ / example2
var myURL = '/search?category=mobile';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?category=mobile&location=california
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?category=mobile&location=new%20york
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search?category=mobile
/ /青年们
var myURL = '/search?location=texas';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?location=california
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?location=new%20york
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search
/ / example4
var myURL = '/search?category=mobile&location=texas';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?category=mobile&location=california
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?category=mobile&location=new%20york
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search?category=mobile
/ / example5
var myURL = 'https://example.com/search?location=texas#fragment';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?location=california#fragment
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?location=new%20york#fragment
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search#fragment
这是函数。
function updateUrl(url,key,value){
if(value!==undefined){
value = encodeURI(value);
}
var hashIndex = url.indexOf("#")|0;
if (hashIndex === -1) hashIndex = url.length|0;
var urls = url.substring(0, hashIndex).split('?');
var baseUrl = urls[0];
var parameters = '';
var outPara = {};
if(urls.length>1){
parameters = urls[1];
}
if(parameters!==''){
parameters = parameters.split('&');
for(k in parameters){
var keyVal = parameters[k];
keyVal = keyVal.split('=');
var ekey = keyVal[0];
var evalue = '';
if(keyVal.length>1){
evalue = keyVal[1];
}
outPara[ekey] = evalue;
}
}
if(value!==undefined){
outPara[key] = value;
}else{
delete outPara[key];
}
parameters = [];
for(var k in outPara){
parameters.push(k + '=' + outPara[k]);
}
var finalUrl = baseUrl;
if(parameters.length>0){
finalUrl += '?' + parameters.join('&');
}
return finalUrl + url.substring(hashIndex);
}
就我所知,上面的答案都没有解决查询字符串包含参数的情况,这些参数本身就是一个数组,因此会出现不止一次,例如:
http://example.com?sizes[]=a&sizes[]=b
下面的函数是我用来更新document.location.search的。它接受一个键/值对数组作为参数,它将返回一个修改后的版本,你可以做任何你想做的事情。我是这样使用的:
var newParams = [
['test','123'],
['best','456'],
['sizes[]','XXL']
];
var newUrl = document.location.pathname + insertParams(newParams);
history.replaceState('', '', newUrl);
如果当前url为:
http://example.com/index.php?test=replaceme&sizes [] = XL
这会让你
http://example.com/index.php?test=123&sizes[]=XL&尺寸[]=XXL&best=456
函数
function insertParams(params) {
var result;
var ii = params.length;
var queryString = document.location.search.substr(1);
var kvps = queryString ? queryString.split('&') : [];
var kvp;
var skipParams = [];
var i = kvps.length;
while (i--) {
kvp = kvps[i].split('=');
if (kvp[0].slice(-2) != '[]') {
var ii = params.length;
while (ii--) {
if (params[ii][0] == kvp[0]) {
kvp[1] = params[ii][1];
kvps[i] = kvp.join('=');
skipParams.push(ii);
}
}
}
}
var ii = params.length;
while (ii--) {
if (skipParams.indexOf(ii) === -1) {
kvps.push(params[ii].join('='));
}
}
result = kvps.length ? '?' + kvps.join('&') : '';
return result;
}