我使用Java从用户获得一个字符串输入。我试着让输入的第一个字母大写。
我试了一下:
String name;
BufferedReader br = new InputStreamReader(System.in);
String s1 = name.charAt(0).toUppercase());
System.out.println(s1 + name.substring(1));
这导致了以下编译错误:
类型不匹配:不能从InputStreamReader转换为BufferedReader 不能在基本类型char上调用toUppercase()
当前回答
你也可以试试这个:
String s1 = br.readLine();
char[] chars = s1.toCharArray();
chars[0] = Character.toUpperCase(chars[0]);
s1= new String(chars);
System.out.println(s1);
这比使用substring更好(优化了)。(但不用担心小弦)
其他回答
谢谢，我已经阅读了一些评论，并带来了以下内容
public static void main(String args[])
{
String myName = "nasser";
String newName = myName.toUpperCase().charAt(0) + myName.substring(1);
System.out.println(newName );
}
我希望它能有所帮助 祝你好运
在Android Studio中
将此依赖项添加到构建中。gradle(模块:app)
dependencies {
...
compile 'org.apache.commons:commons-lang3:3.1'
...
}
现在你可以使用
String string = "STRING WITH ALL CAPPS AND SPACES";
string = string.toLowerCase(); // Make all lowercase if you have caps
someTextView.setText(WordUtils.capitalize(string));
public static String capitalizer(final String texto) {
// split words
String[] palavras = texto.split(" ");
StringBuilder sb = new StringBuilder();
// list of word exceptions
List<String> excessoes = new ArrayList<String>(Arrays.asList("de", "da", "das", "do", "dos", "na", "nas", "no", "nos", "a", "e", "o", "em", "com"));
for (String palavra : palavras) {
if (excessoes.contains(palavra.toLowerCase()))
sb.append(palavra.toLowerCase()).append(" ");
else
sb.append(Character.toUpperCase(palavra.charAt(0))).append(palavra.substring(1).toLowerCase()).append(" ");
}
return sb.toString().trim();
}
class CapitalizeWords
{
public static void main(String[] args)
{
String input ="welcome to kashmiri geeks...";
System.out.println(input);
String[] str = input.split(" ");
for(int i=0; i< str.length; i++)
{
str[i] = (str[i]).substring(0,1).toUpperCase() + (str[i]).substring(1);
}
for(int i=0;i<str.length;i++)
{
System.out.print(str[i]+" ");
}
}
}
String str1 = "hello";
str1.substring(0, 1).toUpperCase()+str1.substring(1);
