我使用Java从用户获得一个字符串输入。我试着让输入的第一个字母大写。

我试了一下:

String name;

BufferedReader br = new InputStreamReader(System.in);

String s1 = name.charAt(0).toUppercase());

System.out.println(s1 + name.substring(1));

这导致了以下编译错误:

类型不匹配:不能从InputStreamReader转换为BufferedReader 不能在基本类型char上调用toUppercase()


当前回答

这是我这边的解决方案,所有条件都检查过了。

   import java.util.Objects;

public class CapitalizeFirstCharacter {

    public static void main(String[] args) {

        System.out.println(capitailzeFirstCharacterOfString("jwala")); //supply input string here
    }

    private static String capitailzeFirstCharacterOfString(String strToCapitalize) {

        if (Objects.nonNull(strToCapitalize) && !strToCapitalize.isEmpty()) {
            return strToCapitalize.substring(0, 1).toUpperCase() + strToCapitalize.substring(1);
        } else {
            return "Null or Empty value of string supplied";

        }

    }

}

其他回答

您可以使用以下代码:

public static void main(String[] args) {

    capitalizeFirstLetter("java");
    capitalizeFirstLetter("java developer");
}

public static void capitalizeFirstLetter(String text) {

    StringBuilder str = new StringBuilder();

    String[] tokens = text.split("\\s");// Can be space,comma or hyphen

    for (String token : tokens) {
        str.append(Character.toUpperCase(token.charAt(0))).append(token.substring(1)).append(" ");
    }
    str.toString().trim(); // Trim trailing space

    System.out.println(str);

}

这是可行的

char[] array = value.toCharArray();

array[0] = Character.toUpperCase(array[0]);

String result = new String(array);

其中一个答案的正确率是95%,但它在我的unitTest中失败了@Ameen Maheen的解决方案几乎完美。除了在输入被转换为String数组之前,您必须修剪输入。所以最完美的一个:

private String convertStringToName(String name) {
        name = name.trim();
        String[] words = name.split(" ");
        StringBuilder sb = new StringBuilder();
        if (words[0].length() > 0) {
            sb.append(Character.toUpperCase(words[0].charAt(0)) + words[0].subSequence(1, words[0].length()).toString().toLowerCase());
            for (int i = 1; i < words.length; i++) {
                sb.append(" ");
                sb.append(Character.toUpperCase(words[i].charAt(0)) + words[i].subSequence(1, words[i].length()).toString().toLowerCase());
            }
        }
        return sb.toString();
    }

这是我这边的解决方案,所有条件都检查过了。

   import java.util.Objects;

public class CapitalizeFirstCharacter {

    public static void main(String[] args) {

        System.out.println(capitailzeFirstCharacterOfString("jwala")); //supply input string here
    }

    private static String capitailzeFirstCharacterOfString(String strToCapitalize) {

        if (Objects.nonNull(strToCapitalize) && !strToCapitalize.isEmpty()) {
            return strToCapitalize.substring(0, 1).toUpperCase() + strToCapitalize.substring(1);
        } else {
            return "Null or Empty value of string supplied";

        }

    }

}
public static String capitalizer(final String texto) {

    // split words
    String[] palavras = texto.split(" ");
    StringBuilder sb = new StringBuilder();

    // list of word exceptions
    List<String> excessoes = new ArrayList<String>(Arrays.asList("de", "da", "das", "do", "dos", "na", "nas", "no", "nos", "a", "e", "o", "em", "com"));

    for (String palavra : palavras) {

        if (excessoes.contains(palavra.toLowerCase()))
            sb.append(palavra.toLowerCase()).append(" ");
        else
            sb.append(Character.toUpperCase(palavra.charAt(0))).append(palavra.substring(1).toLowerCase()).append(" ");
    }
    return sb.toString().trim();
}