如何将本地时间的datetime字符串转换为UTC时间的字符串?

我确信我以前做过这个,但找不到它,所以希望将来能帮助我(和其他人)做到这一点。

澄清:例如,如果我的本地时区(+10)是2008-09-17 14:02:00,我希望生成一个具有等效UTC时间的字符串:2008-09-17 04:02:00。

此外,从http://lucumr.pocoo.org/2011/7/15/eppur-si-muove/请注意,一般来说,这是不可能的,因为DST和其他问题没有从本地时间到UTC时间的唯一转换。


当前回答

在python3:

PIP安装python-dateutil

from dateutil.parser import tz

mydt.astimezone(tz.gettz('UTC')).replace(tzinfo=None) 

其他回答

下面是一些常见的Python时间转换的总结。

有些方法以秒为单位,用(s)标记。可以使用显式公式,如ts = (d - epoch) / unit代替(感谢jfs)。

struct_time (UTC) → POSIX (s):calendar.timegm(struct_time) Naïve datetime (local) → POSIX (s):calendar.timegm(stz.localize(dt, is_dst=None).utctimetuple())(exception during DST transitions, see comment from jfs) Naïve datetime (UTC) → POSIX (s):calendar.timegm(dt.utctimetuple()) Aware datetime → POSIX (s):calendar.timegm(dt.utctimetuple()) POSIX → struct_time (UTC, s):time.gmtime(t)(see comment from jfs) Naïve datetime (local) → struct_time (UTC, s):stz.localize(dt, is_dst=None).utctimetuple()(exception during DST transitions, see comment from jfs) Naïve datetime (UTC) → struct_time (UTC, s):dt.utctimetuple() Aware datetime → struct_time (UTC, s):dt.utctimetuple() POSIX → Naïve datetime (local):datetime.fromtimestamp(t, None)(may fail in certain conditions, see comment from jfs below) struct_time (UTC) → Naïve datetime (local, s):datetime.datetime(struct_time[:6], tzinfo=UTC).astimezone(tz).replace(tzinfo=None)(can't represent leap seconds, see comment from jfs) Naïve datetime (UTC) → Naïve datetime (local):dt.replace(tzinfo=UTC).astimezone(tz).replace(tzinfo=None) Aware datetime → Naïve datetime (local):dt.astimezone(tz).replace(tzinfo=None) POSIX → Naïve datetime (UTC):datetime.utcfromtimestamp(t) struct_time (UTC) → Naïve datetime (UTC, s):datetime.datetime(*struct_time[:6])(can't represent leap seconds, see comment from jfs) Naïve datetime (local) → Naïve datetime (UTC):stz.localize(dt, is_dst=None).astimezone(UTC).replace(tzinfo=None)(exception during DST transitions, see comment from jfs) Aware datetime → Naïve datetime (UTC):dt.astimezone(UTC).replace(tzinfo=None) POSIX → Aware datetime:datetime.fromtimestamp(t, tz)(may fail for non-pytz timezones) struct_time (UTC) → Aware datetime (s):datetime.datetime(struct_time[:6], tzinfo=UTC).astimezone(tz)(can't represent leap seconds, see comment from jfs) Naïve datetime (local) → Aware datetime:stz.localize(dt, is_dst=None)(exception during DST transitions, see comment from jfs) Naïve datetime (UTC) → Aware datetime:dt.replace(tzinfo=UTC)

来源:taaviburns.ca

你可以用:

>>> from time import strftime, gmtime, localtime
>>> strftime('%H:%M:%S', gmtime()) #UTC time
>>> strftime('%H:%M:%S', localtime()) # localtime
def local_to_utc(t):
    secs = time.mktime(t)
    return time.gmtime(secs)

def utc_to_local(t):
    secs = calendar.timegm(t)
    return time.localtime(secs)

来源:http://feihonghsu.blogspot.com/2008/02/converting-from-local-time-to-utc.html

来自bd808的示例用法:如果您的源是一个datetime。Datetime对象t,调用as:

local_to_utc(t.timetuple())

用来避开节衣缩食等。

上面的答案对我没有特别的帮助。下面的代码适用于GMT。

def get_utc_from_local(date_time, local_tz=None):
    assert date_time.__class__.__name__ == 'datetime'
    if local_tz is None:
        local_tz = pytz.timezone(settings.TIME_ZONE) # Django eg, "Europe/London"
    local_time = local_tz.normalize(local_tz.localize(date_time))
    return local_time.astimezone(pytz.utc)

import pytz
from datetime import datetime

summer_11_am = datetime(2011, 7, 1, 11)
get_utc_from_local(summer_11_am)
>>>datetime.datetime(2011, 7, 1, 10, 0, tzinfo=<UTC>)

winter_11_am = datetime(2011, 11, 11, 11)
get_utc_from_local(winter_11_am)
>>>datetime.datetime(2011, 11, 11, 11, 0, tzinfo=<UTC>)

还有一个使用pytz的例子,但是包含了localalize(),这帮了我大忙。

import pytz, datetime
utc = pytz.utc
fmt = '%Y-%m-%d %H:%M:%S'
amsterdam = pytz.timezone('Europe/Amsterdam')

dt = datetime.datetime.strptime("2012-04-06 10:00:00", fmt)
am_dt = amsterdam.localize(dt)
print am_dt.astimezone(utc).strftime(fmt)
'2012-04-06 08:00:00'