如何将本地时间的datetime字符串转换为UTC时间的字符串?
我确信我以前做过这个，但找不到它，所以希望将来能帮助我(和其他人)做到这一点。
澄清:例如，如果我的本地时区(+10)是2008-09-17 14:02:00，我希望生成一个具有等效UTC时间的字符串:2008-09-17 04:02:00。
此外，从http://lucumr.pocoo.org/2011/7/15/eppur-si-muove/请注意，一般来说，这是不可能的，因为DST和其他问题没有从本地时间到UTC时间的唯一转换。
当前回答
简单的
我是这样做的:
>>> utc_delta = datetime.utcnow()-datetime.now()
>>> utc_time = datetime(2008, 9, 17, 14, 2, 0) + utc_delta
>>> print(utc_time)
2008-09-17 19:01:59.999996
的实现
如果你想更花哨一点，你可以把它变成一个函子:
class to_utc():
utc_delta = datetime.utcnow() - datetime.now()
def __call__(cls, t):
return t + cls.utc_delta
结果:
>>> utc_converter = to_utc()
>>> print(utc_converter(datetime(2008, 9, 17, 14, 2, 0)))
2008-09-17 19:01:59.999996
其他回答
在python3:
PIP安装python-dateutil
from dateutil.parser import tz
mydt.astimezone(tz.gettz('UTC')).replace(tzinfo=None)
下面是一些常见的Python时间转换的总结。
有些方法以秒为单位，用(s)标记。可以使用显式公式，如ts = (d - epoch) / unit代替(感谢jfs)。
struct_time (UTC) → POSIX (s):calendar.timegm(struct_time) Naïve datetime (local) → POSIX (s):calendar.timegm(stz.localize(dt, is_dst=None).utctimetuple())(exception during DST transitions, see comment from jfs) Naïve datetime (UTC) → POSIX (s):calendar.timegm(dt.utctimetuple()) Aware datetime → POSIX (s):calendar.timegm(dt.utctimetuple()) POSIX → struct_time (UTC, s):time.gmtime(t)(see comment from jfs) Naïve datetime (local) → struct_time (UTC, s):stz.localize(dt, is_dst=None).utctimetuple()(exception during DST transitions, see comment from jfs) Naïve datetime (UTC) → struct_time (UTC, s):dt.utctimetuple() Aware datetime → struct_time (UTC, s):dt.utctimetuple() POSIX → Naïve datetime (local):datetime.fromtimestamp(t, None)(may fail in certain conditions, see comment from jfs below) struct_time (UTC) → Naïve datetime (local, s):datetime.datetime(struct_time[:6], tzinfo=UTC).astimezone(tz).replace(tzinfo=None)(can't represent leap seconds, see comment from jfs) Naïve datetime (UTC) → Naïve datetime (local):dt.replace(tzinfo=UTC).astimezone(tz).replace(tzinfo=None) Aware datetime → Naïve datetime (local):dt.astimezone(tz).replace(tzinfo=None) POSIX → Naïve datetime (UTC):datetime.utcfromtimestamp(t) struct_time (UTC) → Naïve datetime (UTC, s):datetime.datetime(*struct_time[:6])(can't represent leap seconds, see comment from jfs) Naïve datetime (local) → Naïve datetime (UTC):stz.localize(dt, is_dst=None).astimezone(UTC).replace(tzinfo=None)(exception during DST transitions, see comment from jfs) Aware datetime → Naïve datetime (UTC):dt.astimezone(UTC).replace(tzinfo=None) POSIX → Aware datetime:datetime.fromtimestamp(t, tz)(may fail for non-pytz timezones) struct_time (UTC) → Aware datetime (s):datetime.datetime(struct_time[:6], tzinfo=UTC).astimezone(tz)(can't represent leap seconds, see comment from jfs) Naïve datetime (local) → Aware datetime:stz.localize(dt, is_dst=None)(exception during DST transitions, see comment from jfs) Naïve datetime (UTC) → Aware datetime:dt.replace(tzinfo=UTC)
来源:taaviburns.ca
简单地说，要将任何datetime日期转换为UTC时间:
from datetime import datetime
def to_utc(date):
return datetime(*date.utctimetuple()[:6])
让我们用一个例子来解释。首先，我们需要从字符串中创建一个datetime:
>>> date = datetime.strptime("11 Feb 2011 17:33:54 -0800", "%d %b %Y %H:%M:%S %z")
然后，我们可以调用函数:
>>> to_utc(date)
datetime.datetime(2011, 2, 12, 1, 33, 54)
函数如何一步步工作:
>>> date.utctimetuple()
time.struct_time(tm_year=2011, tm_mon=2, tm_mday=12, tm_hour=1, tm_min=33, tm_sec=54, tm_wday=5, tm_yday=43, tm_isdst=0)
>>> date.utctimetuple()[:6]
(2011, 2, 12, 1, 33, 54)
>>> datetime(*date.utctimetuple()[:6])
datetime.datetime(2011, 2, 12, 1, 33, 54)
你可以用:
>>> from time import strftime, gmtime, localtime
>>> strftime('%H:%M:%S', gmtime()) #UTC time
>>> strftime('%H:%M:%S', localtime()) # localtime
谢谢@rofly，从字符串到字符串的完整转换如下:
import time
time.strftime("%Y-%m-%d %H:%M:%S",
time.gmtime(time.mktime(time.strptime("2008-09-17 14:04:00",
"%Y-%m-%d %H:%M:%S"))))
我对时间/日历功能的总结:
time.strptime 字符串——>元组(没有应用时区，所以匹配字符串)
time.mktime 本地时间元组——自epoch以来>秒(始终是本地时间)
time.gmtime seconds since epoch——UTC中的>元组
and
calendar.timegm tuple in UTC——> seconds since epoch
time.localtime 自epoch ->元组在本地时区的秒数
