请问如何在ASP中获取客户端IP地址?NET时使用MVC 6。 请求。ServerVariables["REMOTE_ADDR"]无效。


当前回答

在ASP。NET 2.1,在StartUp.cs中添加此服务:

services.AddHttpContextAccessor();
services.TryAddSingleton<IActionContextAccessor, ActionContextAccessor>();

然后做3步:

在MVC控制器中定义一个变量 private IHttpContextAccessor _accessor DI转换为控制器的构造函数 IHttpContextAccessor访问器 { _accessor = accessor; } 检索IP地址 _accessor.HttpContext.Connection.RemoteIpAddress.ToString ()

事情是这样的。

其他回答

您还可以使用api.db-ip.com web服务获取IP地址和位置。

这项服务是免费的,但有一个限制:每天1000次请求。

public string GetRemoteIP()
{
    HttpClient client = new HttpClient();
    var result = client.GetStringAsync("https://api.db-ip.com/v2/free/self").Result;
    var ip = JsonSerializer.Deserialize<RemoteIPDto>(result.ToString()).IP;
    return ip;
}
public static string GetUserAddress()
{
      HttpClient client = new HttpClient();
      var result = client.GetStringAsync("https://api.db-ip.com/v2/free/self").Result;
      var location = result.ToString();
      return remoteAddress;
}

RemoteIPDto类在哪里

public class RemoteIPDto
{
    [JsonPropertyName("ipAddress")]
    public string IP { get; set; }
    [JsonPropertyName("continentCode")]
    public string ContinentCode { get; set; }
    [JsonPropertyName("continentName")]
    public string ContinentName { get; set; }
    [JsonPropertyName("countryCode")]
    public string CountryCode { get; set; }
    [JsonPropertyName("countryName")]
    public string CountryName { get; set; }
    [JsonPropertyName("city")]
    public string City { get; set; }
}

也可以从外部服务获取IP。

public string GetIP()
{
    HttpClient client = new HttpClient();
    var result = client.GetStringAsync("https://jsonip.com/").Result;
    var ip = JsonSerializer.Deserialize<RemoteIPDto>(result.ToString()).IP;
    return ip;
}

RemoteIPDto类在哪里

public class RemoteIPDto
{
    [JsonPropertyName("ip")]
    public string IP { get; set; }
    [JsonPropertyName("geo-ip")]
    public string GeoIp { get; set; }
    [JsonPropertyName("API Help")]
    public string ApiHelp { get; set; }
}

可以添加一些回退逻辑来处理负载均衡器的存在。

此外,通过检查,即使没有负载均衡器,X-Forwarded-For报头也会被设置(可能是因为额外的Kestrel层?):

public string GetRequestIP(bool tryUseXForwardHeader = true)
{
    string ip = null;

    // todo support new "Forwarded" header (2014) https://en.wikipedia.org/wiki/X-Forwarded-For

    // X-Forwarded-For (csv list):  Using the First entry in the list seems to work
    // for 99% of cases however it has been suggested that a better (although tedious)
    // approach might be to read each IP from right to left and use the first public IP.
    // http://stackoverflow.com/a/43554000/538763
    //
    if (tryUseXForwardHeader)
        ip = GetHeaderValueAs<string>("X-Forwarded-For").SplitCsv().FirstOrDefault();

    // RemoteIpAddress is always null in DNX RC1 Update1 (bug).
    if (ip.IsNullOrWhitespace() && _httpContextAccessor.HttpContext?.Connection?.RemoteIpAddress != null)
        ip = _httpContextAccessor.HttpContext.Connection.RemoteIpAddress.ToString();

    if (ip.IsNullOrWhitespace())
        ip = GetHeaderValueAs<string>("REMOTE_ADDR");

    // _httpContextAccessor.HttpContext?.Request?.Host this is the local host.

    if (ip.IsNullOrWhitespace())
        throw new Exception("Unable to determine caller's IP.");

    return ip;
}

public T GetHeaderValueAs<T>(string headerName)
{
    StringValues values;

    if (_httpContextAccessor.HttpContext?.Request?.Headers?.TryGetValue(headerName, out values) ?? false)
    {
        string rawValues = values.ToString();   // writes out as Csv when there are multiple.

        if (!rawValues.IsNullOrWhitespace())
            return (T)Convert.ChangeType(values.ToString(), typeof(T));
    }
    return default(T);
}

public static List<string> SplitCsv(this string csvList, bool nullOrWhitespaceInputReturnsNull = false)
{
    if (string.IsNullOrWhiteSpace(csvList))
        return nullOrWhitespaceInputReturnsNull ? null : new List<string>();

    return csvList
        .TrimEnd(',')
        .Split(',')
        .AsEnumerable<string>()
        .Select(s => s.Trim())
        .ToList();
}

public static bool IsNullOrWhitespace(this string s)
{
    return String.IsNullOrWhiteSpace(s);
}

假设_httpContextAccessor通过DI提供。

根据官方文档,如果你使用Apache或Nginx集成,以下代码应该添加到启动。ConfigureServices方法。

// using Microsoft.AspNetCore.HttpOverrides;

    services.Configure<ForwardedHeadersOptions>(options =>
    {
        options.ForwardedHeaders = ForwardedHeaders.XForwardedFor | 
            ForwardedHeaders.XForwardedProto;
        // Only loopback proxies are allowed by default.
        // Clear that restriction because forwarders are enabled by explicit 
        // configuration.
        options.KnownNetworks.Clear();
        options.KnownProxies.Clear();
    });

最重要的是,在配置方法中使用

app.UseForwardedHeaders();

进一步假设在nginx conf文件中,在一个位置内,使用

proxy_set_header   Host $host;
proxy_set_header   X-Real-IP $remote_addr;
proxy_set_header   X-Forwarded-For $proxy_add_x_forwarded_for;
proxy_set_header   X-Forwarded-Host $server_name;

现在X-Forwarded-For中的第一个条目将是真正的客户端IP。

重要:如果你想保护应用程序,不允许攻击者注入x - forward - for,请阅读这个答案。

请参见转发Linux和非iis反向代理方案、配置Nginx和处理无效报头

注意:当使用localhost时,IP地址总是“0.0.0.1”,但当我在AWS EC2实例上使用Nginx托管应用程序时,我收到了正确的IP地址。

将以下包添加到您的项目中:

"Microsoft.AspNetCore.HttpOverrides": "2.2.0"

然后在Startup.cs中的Configure()方法中添加以下内容(确保将其放在app.UseStaticFiles()和app.UseRouting()之前)

app.UseForwardedHeaders(new ForwardedHeadersOptions
{
    ForwardedHeaders = ForwardedHeaders.XForwardedFor | ForwardedHeaders.XForwardedProto
});
    
// app.UseStaticFiles();
// app.UseRouting();

然后在你的控制器类中,你可以使用下面的代码获取IP地址:

IPAddress remoteIpAddress = Request.HttpContext.Connection.RemoteIpAddress.MapToIPv4()?.ToString();