我想使用c#检查字符串值是否包含字符串数组中的单词。例如,

string stringToCheck = "text1text2text3";

string[] stringArray = { "text1", "someothertext", etc... };

if(stringToCheck.contains stringArray) //one of the items?
{

}

我如何检查字符串值'stringToCheck'是否包含数组中的一个词?


当前回答

Try:

String[] val = { "helloword1", "orange", "grape", "pear" };
String sep = "";
string stringToCheck = "word1";

bool match = String.Join(sep,val).Contains(stringToCheck);
bool anothermatch = val.Any(s => s.Contains(stringToCheck));

其他回答

这些解决方案大多数是正确的,但如果你需要检查值不区分大小写:

using System.Linq;
...
string stringToCheck = "text1text2text3";
string[] stringArray = { "text1", "someothertext"};

if(stringArray.Any(a=> String.Equals(a, stringToCheck, StringComparison.InvariantCultureIgnoreCase)) )
{
   //contains
}

if (stringArray.Any(w=> w.IndexOf(stringToCheck, StringComparison.InvariantCultureIgnoreCase)>=0))
{
   //contains
}

dotNetFiddle例子

Try:

String[] val = { "helloword1", "orange", "grape", "pear" };
String sep = "";
string stringToCheck = "word1";

bool match = String.Join(sep,val).Contains(stringToCheck);
bool anothermatch = val.Any(s => s.Contains(stringToCheck));

我使用下面的代码来检查字符串是否包含字符串数组中的任何项:

foreach (string s in stringArray)
{
    if (s != "")
    {
        if (stringToCheck.Contains(s))
        {
            Text = "matched";
        }
    }
}
⚠️ Note: this does not answer the question asked
The question asked is "how can I check if a sentence contains any word from a list of words?"
This answer checks if a list of words contains one particular word

我在控制台应用程序中使用以下命令检查参数

var sendmail = args.Any( o => o.ToLower() == "/sendmail=true");

我使用了类似于Maitrey684的IndexOf方法和Theomax的foreach循环来创建它。(注意:前3个“字符串”行只是一个例子,你可以创建一个数组,并把它变成适当的格式)。

如果您想比较两个数组,它们将以分号分隔,但最后一个值后面不会有分号。如果你在数组的字符串形式中添加了一个分号(即a;b;c变成了a;b;c;),你可以使用"x;"进行匹配,无论它在什么位置:

bool found = false;
string someString = "a-b-c";
string[] arrString = someString.Split('-');
string myStringArray = arrString.ToString() + ";";

foreach (string s in otherArray)
{
    if (myStringArray.IndexOf(s + ";") != -1) {
       found = true;
       break;
    }
}

if (found == true) { 
    // ....
}