考虑:

http://example.com/page.html?returnurl=%2Fadmin

对于page.html内的js,它如何检索GET参数?

对于上面的简单例子,func('returnurl')应该是/admin。

但它也应该适用于复杂的查询字符串…


当前回答

获取JSON对象的参数:

console.log(getUrlParameters())

function getUrlParameters() {
    var out = {};
    var str = window.location.search.replace("?", "");
    var subs = str.split(`&`).map((si)=>{var keyVal = si.split(`=`); out[keyVal[0]]=keyVal[1];});
    return out
}

其他回答

Window.location.search将返回?上。下面的代码将删除?,使用split将键/值数组分开,然后将命名属性分配给params对象:

function getSearchParameters() {
    var prmstr = window.location.search.substr(1);
    return prmstr != null && prmstr != "" ? transformToAssocArray(prmstr) : {};
}

function transformToAssocArray( prmstr ) {
    var params = {};
    var prmarr = prmstr.split("&");
    for ( var i = 0; i < prmarr.length; i++) {
        var tmparr = prmarr[i].split("=");
        params[tmparr[0]] = tmparr[1];
    }
    return params;
}

var params = getSearchParameters();

然后,您可以通过调用params.test从http://myurl.com/?test=1获取测试参数。

你应该使用URL和URLSearchParams本地函数:

let url = new url ("https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8&q=mdn%20query%20string") let params = new URLSearchParams(url.search); Let sourceid = params.get('sourceid') // 'chrome-instant' Let q = params.get('q') // 'mdn查询字符串' 让ie = params.has('ie') // true params.append(“平”、“乒乓球”) console.log (sourceid) console.log (q) console.log (ie) console.log (params.toString ()) console.log (params.get(“平”))

https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams https://polyfill.io/v2/docs/features/

我这样做(检索一个特定的get-parameter,这里'parameterName'):

var parameterValue = decodeURIComponent(window.location.search.match(/(\?|&)parameterName\=([^&]*)/)[2]);

获取JSON对象的参数:

console.log(getUrlParameters())

function getUrlParameters() {
    var out = {};
    var str = window.location.search.replace("?", "");
    var subs = str.split(`&`).map((si)=>{var keyVal = si.split(`=`); out[keyVal[0]]=keyVal[1];});
    return out
}

我的解决方案扩展了@tak3r的。

当没有查询参数时返回空对象,并支持数组符号?a=1&a=2&a=3:

function getQueryParams () {
  function identity (e) { return e; }
  function toKeyValue (params, param) {
    var keyValue = param.split('=');
    var key = keyValue[0], value = keyValue[1];

    params[key] = params[key]?[value].concat(params[key]):value;
    return params;
  }
  return decodeURIComponent(window.location.search).
    replace(/^\?/, '').split('&').
    filter(identity).
    reduce(toKeyValue, {});
}