dr解决方案在一行代码上使用普通JavaScript

var queryDict = {}
location.search.substr(1).split("&").forEach(function(item) {queryDict[item.split("=")[0]] = item.split("=")[1]})

这是最简单的解决方案。不幸的是，它不能处理多值键和编码字符。

"?a=1&a=%2Fadmin&b=2&c=3&d&e"
> queryDict
a: "%2Fadmin"  // Overridden with the last value, not decoded.
b: "2"
c: "3"
d: undefined
e: undefined

多值键和编码字符?

请参阅如何在JavaScript中获得查询字符串值的原始答案。

"?a=1&b=2&c=3&d&e&a=5&a=t%20e%20x%20t&e=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dståle%26car%3Dsaab&a=%2Fadmin"
> queryDict
a: ["1", "5", "t e x t", "/admin"]
b: ["2"]
c: ["3"]
d: [undefined]
e: [undefined, "http://w3schools.com/my test.asp?name=ståle&car=saab"]

在你的例子中，你可以像这样访问这个值:

"?returnurl=%2Fadmin"
> qd.returnurl    // ["/admin"]
> qd['returnurl'] // ["/admin"]
> qd.returnurl[0] // "/admin"

你应该使用URL和URLSearchParams本地函数:

let url = new url ("https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8&q=mdn%20query%20string") let params = new URLSearchParams(url.search); Let sourceid = params.get('sourceid') // 'chrome-instant' Let q = params.get('q') // 'mdn查询字符串' 让ie = params.has('ie') // true params.append(“平”、“乒乓球”) console.log (sourceid) console.log (q) console.log (ie) console.log (params.toString ()) console.log (params.get(“平”))

https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams https://polyfill.io/v2/docs/features/

我这样做(检索一个特定的get-parameter，这里'parameterName'):

var parameterValue = decodeURIComponent(window.location.search.match(/(\?|&)parameterName\=([^&]*)/)[2]);

获取JSON对象的参数:

console.log(getUrlParameters())

function getUrlParameters() {
    var out = {};
    var str = window.location.search.replace("?", "");
    var subs = str.split(`&`).map((si)=>{var keyVal = si.split(`=`); out[keyVal[0]]=keyVal[1];});
    return out
}

一种更花哨的方法::)

var options = window.location.search.slice(1)
                      .split('&')
                      .reduce(function _reduce (/*Object*/ a, /*String*/ b) {
                        b = b.split('=');
                        a[b[0]] = decodeURIComponent(b[1]);
                        return a;
                      }, {});

这个解决方案处理URL解码:

var params = function() {
    function urldecode(str) {
        return decodeURIComponent((str+'').replace(/\+/g, '%20'));
    }

    function transformToAssocArray( prmstr ) {
        var params = {};
        var prmarr = prmstr.split("&");
        for ( var i = 0; i < prmarr.length; i++) {
            var tmparr = prmarr[i].split("=");
            params[tmparr[0]] = urldecode(tmparr[1]);
        }
        return params;
    }

    var prmstr = window.location.search.substr(1);
    return prmstr != null && prmstr != "" ? transformToAssocArray(prmstr) : {};
}();

用法:

console.log('someParam GET value is', params['someParam']);