基于@Halil的伟大回答，这里是一个简单的函数如何在特定的键后插入新元素， 同时保留整型键:

private function arrayInsertAfterKey($array, $afterKey, $key, $value){
    $pos   = array_search($afterKey, array_keys($array));

    return array_merge(
        array_slice($array, 0, $pos, $preserve_keys = true),
        array($key=>$value),
        array_slice($array, $pos, $preserve_keys = true)
    );
} 

可以在整数和字符串位置进行插入的函数:

/**
 * @param array      $array
 * @param int|string $position
 * @param mixed      $insert
 */
function array_insert(&$array, $position, $insert)
{
    if (is_int($position)) {
        array_splice($array, $position, 0, $insert);
    } else {
        $pos   = array_search($position, array_keys($array));
        $array = array_merge(
            array_slice($array, 0, $pos),
            $insert,
            array_slice($array, $pos)
        );
    }
}

整数的用法:

$arr = ["one", "two", "three"];
array_insert(
    $arr,
    1,
    "one-half"
);
// ->
array (
  0 => 'one',
  1 => 'one-half',
  2 => 'two',
  3 => 'three',
)

字符串的用法:

$arr = [
    "name"  => [
        "type"      => "string",
        "maxlength" => "30",
    ],
    "email" => [
        "type"      => "email",
        "maxlength" => "150",
    ],
];

array_insert(
    $arr,
    "email",
    [
        "phone" => [
            "type"   => "string",
            "format" => "phone",
        ],
    ]
);
// ->
array (
  'name' =>
  array (
    'type' => 'string',
    'maxlength' => '30',
  ),
  'phone' =>
  array (
    'type' => 'string',
    'format' => 'phone',
  ),
  'email' =>
  array (
    'type' => 'email',
    'maxlength' => '150',
  ),
)

如何使用array_splice()保存数组键

@jay的答案。Lee是正确的，不幸的是，它不能保存数组的键，正如评论中指出的那样:

$original = array( 
    'a' => 'A', 
    'b' => 'B', 
    'c' => 'C', 
    // insert here
    'd' => 'D', 
    'e' => 'E');

$inserted = array( 'x' => 'X' ); 

array_splice( $original, 3, 0, $inserted );
print_r($original);

/* Output
Array
(
    [a] => A
    [b] => B
    [c] => C
    [0] => X  <= the lost key 
    [d] => D
    [e] => E
) */

我发现保存数组键的最简单的方法是使用array_splice()函数，并使用+ /联合操作符将数组添加在一起(也在另一个答案的评论中提到):

$original = array( 
    'a' => 'A', 
    'b' => 'B', 
    'c' => 'C', 
    // insert here
    'd' => 'D', 
    'e' => 'E');

$inserted = array( 'x' => 'X' ); 

// Insert before postion 'd'
$before = array_splice( $original, 0, 3 ); // $original contains the left over

// Merge together
$result = $before + $inserted + $original;
print_r($result);

/* Output
Array
(
    [a] => A
    [b] => B
    [c] => C
    [x] => X
    [d] => D
    [e] => E
) */

注意:使用数组联合操作符仅在处理非数字键时是安全的

谢谢你的更正@mickmackusa

你可以用这个

foreach ($array as $key => $value) 
{
    if($key==1)
    {
        $new_array[]=$other_array;
    }   
    $new_array[]=$value;    
}

这也是一个有效的解决方案:

function array_insert(&$array,$element,$position=null) {
  if (count($array) == 0) {
    $array[] = $element;
  }
  elseif (is_numeric($position) && $position < 0) {
    if((count($array)+position) < 0) {
      $array = array_insert($array,$element,0);
    }
    else {
      $array[count($array)+$position] = $element;
    }
  }
  elseif (is_numeric($position) && isset($array[$position])) {
    $part1 = array_slice($array,0,$position,true);
    $part2 = array_slice($array,$position,null,true);
    $array = array_merge($part1,array($position=>$element),$part2);
    foreach($array as $key=>$item) {
      if (is_null($item)) {
        unset($array[$key]);
      }
    }
  }
  elseif (is_null($position)) {
    $array[] = $element;
  }  
  elseif (!isset($array[$position])) {
    $array[$position] = $element;
  }
  $array = array_merge($array);
  return $array;
}

获奖者: http://binarykitten.com/php/52-php-insert-element-and-shift.html

试试这个:

$colors = array('red', 'blue', 'yellow');

$colors = insertElementToArray($colors, 'green', 2);


function insertElementToArray($arr = array(), $element = null, $index = 0)
{
    if ($element == null) {
        return $arr;
    }

    $arrLength = count($arr);
    $j = $arrLength - 1;

    while ($j >= $index) {
        $arr[$j+1] = $arr[$j];
        $j--;
    }

    $arr[$index] = $element;

    return $arr;
}