如何将一个新项目插入到数组的任何位置,例如在数组的中间?
当前回答
在做了几天之后,这是我能找到的最简单的解决方案。
$indexnumbertoaddat // this is a variable that points to the index # where you
want the new array to be inserted
$arrayToAdd = array(array('key' => $value, 'key' => $value)); //this is the new
array and it's values that you want to add. //the key here is to write it like
array(array('key' =>, since you're adding this array inside another array. This
is the point that a lot of answer left out.
array_splice($originalArray, $indexnumbertoaddatt, 0, $arrayToAdd); //the actual
splice function. You're doing it to $originalArray, at the index # you define,
0 means you're just shifting all other index items down 1, and then you add the
new array.
其他回答
要将元素插入到具有字符串键的数组中,您可以这样做:
/* insert an element after given array key
* $src = array() array to work with
* $ins = array() to insert in key=>array format
* $pos = key that $ins will be inserted after
*/
function array_insert_string_keys($src,$ins,$pos) {
$counter=1;
foreach($src as $key=>$s){
if($key==$pos){
break;
}
$counter++;
}
$array_head = array_slice($src,0,$counter);
$array_tail = array_slice($src,$counter);
$src = array_merge($array_head, $ins);
$src = array_merge($src, $array_tail);
return($src);
}
没有本地PHP函数(据我所知)可以完全完成您的请求。
我已经写了2个我认为适合目的的方法:
function insertBefore($input, $index, $element) {
if (!array_key_exists($index, $input)) {
throw new Exception("Index not found");
}
$tmpArray = array();
$originalIndex = 0;
foreach ($input as $key => $value) {
if ($key === $index) {
$tmpArray[] = $element;
break;
}
$tmpArray[$key] = $value;
$originalIndex++;
}
array_splice($input, 0, $originalIndex, $tmpArray);
return $input;
}
function insertAfter($input, $index, $element) {
if (!array_key_exists($index, $input)) {
throw new Exception("Index not found");
}
$tmpArray = array();
$originalIndex = 0;
foreach ($input as $key => $value) {
$tmpArray[$key] = $value;
$originalIndex++;
if ($key === $index) {
$tmpArray[] = $element;
break;
}
}
array_splice($input, 0, $originalIndex, $tmpArray);
return $input;
}
虽然速度更快,而且可能更节省内存,但这只适用于不需要维护数组键的地方。
如果你确实需要维护密钥,下面的方法会更合适;
function insertBefore($input, $index, $newKey, $element) {
if (!array_key_exists($index, $input)) {
throw new Exception("Index not found");
}
$tmpArray = array();
foreach ($input as $key => $value) {
if ($key === $index) {
$tmpArray[$newKey] = $element;
}
$tmpArray[$key] = $value;
}
return $input;
}
function insertAfter($input, $index, $newKey, $element) {
if (!array_key_exists($index, $input)) {
throw new Exception("Index not found");
}
$tmpArray = array();
foreach ($input as $key => $value) {
$tmpArray[$key] = $value;
if ($key === $index) {
$tmpArray[$newKey] = $element;
}
}
return $tmpArray;
}
$result_array = array();
$array = array("Tim","John","Mark");
$new_element = "Bill";
$position = 1;
for ($i=0; $i<count($array); $i++)
{
if ($i==$position)
{
$result_array[] = $new_element;
}
$result_array[] = $array[$i];
}
print_r($result_array);
// Result will Array([0] => "Tim",[1] => "Bill", [2] => "John",[1] => "Mark")
这也是一个有效的解决方案:
function array_insert(&$array,$element,$position=null) {
if (count($array) == 0) {
$array[] = $element;
}
elseif (is_numeric($position) && $position < 0) {
if((count($array)+position) < 0) {
$array = array_insert($array,$element,0);
}
else {
$array[count($array)+$position] = $element;
}
}
elseif (is_numeric($position) && isset($array[$position])) {
$part1 = array_slice($array,0,$position,true);
$part2 = array_slice($array,$position,null,true);
$array = array_merge($part1,array($position=>$element),$part2);
foreach($array as $key=>$item) {
if (is_null($item)) {
unset($array[$key]);
}
}
}
elseif (is_null($position)) {
$array[] = $element;
}
elseif (!isset($array[$position])) {
$array[$position] = $element;
}
$array = array_merge($array);
return $array;
}
获奖者: http://binarykitten.com/php/52-php-insert-element-and-shift.html
你可能会觉得这更直观一些。它只需要调用array_splice一个函数:
$original = array( 'a', 'b', 'c', 'd', 'e' );
$inserted = array( 'x' ); // not necessarily an array, see manual quote
array_splice( $original, 3, 0, $inserted ); // splice in at position 3
// $original is now a b c x d e
如果replacement只是一个元素,则没有必要在它周围加上array(),除非该元素本身是数组、对象或NULL。
RETURN VALUE:需要注意的是,函数不返回所需的替换。$original通过引用传递,并在适当的位置进行编辑。请参阅参数列表中带有&的表达式array &$array。